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Sladkaya [172]
3 years ago
14

Which inequality is shown on this number line?

Mathematics
1 answer:
shutvik [7]3 years ago
3 0

Answer:

Less than 26 (>26)

Step-by-step explanation:

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What are the exponent and coefficient of the expression 4b-^3
gulaghasi [49]

9514 1404 393

Answer:

  • exponent: -3
  • coefficient: 4

Step-by-step explanation:

The coefficient of a term is its constant multiplier. The exponent is the power to which the base is raised.

The term 4·b^(-3) has an exponent of -3, a base of b and a coefficient of 4.

The exponent is -3; the coefficient is 4.

6 0
2 years ago
Read 2 more answers
Given the equation y = 2x - 5 and the domain {-1, 4} find the slope
Ksivusya [100]

Answer:

The slope  is m=2

Step-by-step explanation:

we have

y=2x-5

This is the equation of a line in slope intercept form

y=mx+b

where

m is the slope

b is the y-coordinate of the y-intercept

therefore

The slope m is equal to

m=2

<em>Alternative Method</em>

we know that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have

y=2x-5  and the domain {-1, 4}

For x=-1

y=2(-1)-5=-7

point (-1,-7)

For x=4

y=2(4)-5=3

point (4,3)

substitute the values in the formula of the slope

m=\frac{3+7}{4+1}

m=\frac{10}{5}

m=2

8 0
3 years ago
The formula A=1w is used to calculate the area A of a rectangle surface using the length(l) and the width (w) of the surface whi
Sedaia [141]
A = lw

To isolate w, you have to divide l on both sides:
w = A/l
7 0
3 years ago
Please assist me with this problem
Anna11 [10]

Answer:

Option B is not a justification

Step-by-step explanation:

Option A is a justification (to get two pair of similar triangles (ABC-ACD) and (ABC-BCD))

Option C is a justification (a^2 = cy, b^2 = cx, a^2 + b^2 = cy + cx)

Option D is a justification (a^2 + b^2 = cy + cx = c(y + x) = c^2)

=> Option B is not a justification

8 0
3 years ago
Find all points having an x-coordinate of 2 whose distance from the point (-1,-2) is 5
mariarad [96]
The\ equation\ of\ the\ circle:(x-a)^2+(y-b)^2=r^2\\\\where\ (a;\ b)\ -the\ coordinates\ of\ the\ center;\ r-the\ radius\\-----------------------------\\(-1;-2)-the\ center\ of\ the\ circle\\r=5\\\\The\ equation:(x+1)^2+(y+2)^2=5^5\\\\Put\ x=2\ to\ the\ equation:\\\\(2+1)^2+(y+2)^2=25\\3^2+(y+2)^2=25\\9+(y+2)^2=25\\(y+2)^2=25-9\\(y+2)^2=16\iff y+1=\pm\sqrt{16}\\\\y+1=-4\ or\ y+1=4\ \ \ \ \ |subtract\ 1\ from\ both \sides\\y=-5\ or\ y=3\\\\Answer:(2;-5)\ and\ (2;\ 3).
5 0
3 years ago
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