Since you don't know the value of b about the best that you could do is:
(2b)^4
16b^4
16b*b*b*b
We know that sin2x=2sinxcosx
(search the net for proof if you wish)
So the original equation becomes
2sinxcosx-sinx=0
The two terms both have sinx that can be taken out to get:
sinx(2cosx-1)=0
This is true if sinx=0 or 2cosx-1=0 , rewritten: cosx=1/2
sinx=0 than x=2kπ
cosx=1/2 than x=π/3+2kπ
where k is an integer
Hello,
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Answer:
Step-by-step explanation:
(3x+1)(x-3)-(2-2x^2-3x)
3x^2+x-9x-3-2+2x^2+3x
3x^2+2x^2+x-9x+3x-3-2
5x^2-5x-5
the constant term in the simplified expression is -5.
