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iren2701 [21]
3 years ago
12

Solve this proportion: 5/9 /20=5.5/x

Mathematics
1 answer:
Slav-nsk [51]3 years ago
8 0
X=0.495 if you are solving for x
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In the trepezium,a=7cm,b=10.4cm and h=6.7cm.work out the area of the trepezium.​
Nataly [62]

Answer:

58.29

Step-by-step explanation:

1/2 × (7+10.4) × 6.7

= 58.29

3 0
3 years ago
The sum of 9 and a number is less than 12. Which of the following
Fofino [41]

Answer:

9+x<12

Step-by-step explanation:

add 9 to an unknown number.

9+x

use the < less than symbol (instead of an equal sign) and write 12.

3 0
3 years ago
Read 2 more answers
In the circle below, DB = 22 cm, and m&lt;DBC = 60°. Find BC. Ignore my handwriting.​
Karo-lina-s [1.5K]

Answer:

BC=11\ cm

Step-by-step explanation:

step 1

Find the measure of the arc DC

we know that

The inscribed angle measures half of the arc comprising

m\angle DBC=\frac{1}{2}[arc\ DC]

substitute the values

60\°=\frac{1}{2}[arc\ DC]

120\°=arc\ DC

arc\ DC=120\°

step 2

Find the measure of arc BC

we know that

arc\ DC+arc\ BC=180\° ----> because the diameter BD divide the circle into two equal parts

120\°+arc\ BC=180\°

arc\ BC=180\°-120\°=60\°

step 3

Find the measure of angle BDC

we know that

The inscribed angle measures half of the arc comprising

m\angle BDC=\frac{1}{2}[arc\ BC]

substitute the values

m\angle BDC=\frac{1}{2}[60\°]

m\angle BDC=30\°

therefore

The triangle DBC is a right triangle ---> 60°-30°-90°

step 4

Find the measure of BC

we know that

In the right triangle DBC

sin(\angle BDC)=BC/BD

BC=(BD)sin(\angle BDC)

substitute the values

BC=(22)sin(30\°)=11\ cm

6 0
4 years ago
PLEASE HELP! ASAP! WILL MARK BRAINLIEST IF CORRECT!!!!!
Volgvan

Answer:

D.............................................

Step-by-step explanation:

im sorry if im wrong

6 0
3 years ago
7) The table shows the cost to play at Mini-golf Course A. The equation y = 4x + 5 models the cost (y) to play x games at Mini-g
LenKa [72]

Answer:

The answer is A.

Step-by-step explanation:

took the test im positive

3 0
2 years ago
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