Answer:
Explanation:
Given that,
A point charge is placed between two charges
Q1 = 4 μC
Q2 = -1 μC
Distance between the two charges is 1m
We want to find the point when the electric field will be zero.
Electric field can be calculated using
E = kQ/r²
Let the point charge be at a distance x from the first charge Q1, then, it will be at 1 -x from the second charge.
Then, the magnitude of the electric at point x is zero.
E = kQ1 / r² + kQ2 / r²
0 = kQ1 / x² - kQ2 / (1-x)²
kQ1 / x² = kQ2 / (1-x)²
Divide through by k
Q1 / x² = Q2 / (1-x)²
4μ / x² = 1μ / (1 - x)²
Divide through by μ
4 / x² = 1 / (1-x)²
Cross multiply
4(1-x)² = x²
4(1-2x+x²) = x²
4 - 8x + 4x² = x²
4x² - 8x + 4 - x² = 0
3x² - 8x + 4 = 0
Check attachment for solution of quadratic equation
We found that,
x = 2m or x = ⅔m
So, the electric field will be zero if placed ⅔m from point charge A, OR ⅓m from point charge B.
Explanation:
It"s B i think i've might be wrong??
Answer:
A 1.56 see below
Explanation:
I will assume the 45 degree force is upward
vertical component = 600 sin 45 = 424.26 N
added to the other vertical force will total 824.26 N
F = ma
824.26 = 100 * a shows a = 8.24 m/s upward
Now we have to assume the mass is ALSO acted on by gravity and this value is given as 9.8 ( so downward is positive)
9.81 - 8.24 = 1.56 m/s^2
Answer:
B. MASS & MATTER
Explanation:
Newton's law also states that the strength of gravity between any two objects depends on two factors: the masses of the objects and the distance between them. Objects with greater mass have a stronger force of gravity between them.
Answer:
re = 2.09 Å.
Explanation:
As the electron is moving around the stationary proton along a circular path at a constant speed, there exists a force that keeps the electron within this trajectory, which is the centripetal force.
This centripetal force, is no other than the attractive electric force between the proton and the electron, so we can write the following equality:
Fe = Fc ⇒ k*Qp*Qe / re² = me*ve²/re
⇒ re = k*Qp*Qe / m*ve², where:
k = 9*10⁹ N, Qp =-Qe= 1.6*10⁻¹⁹ coul, me =9.1*10⁻³¹ kg, and ve= 1.1*10⁶m/s
⇒ re = 9*(1.6)²*10⁻²⁹ / 9.1*(1.1)²*10⁻¹⁹ m
⇒ re = 2.09*10⁻¹⁰ m = 2.09 Å.