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lubasha [3.4K]
3 years ago
11

Can someone please help me? If somebody pushes a cart with 4N of force and the cart moves a distance of 2 meters, how much work

did they do?
Physics
1 answer:
sergeinik [125]3 years ago
7 0

Answer:

Work done, W = 8 J

Explanation:

We have,

Force acting on the cart is 4 N

Cart covers a distance of 2 m

We need to find the work done by the cart. Work done by an object is given in terms of force and displacement. It can be given by :

W=Fd\\\\W=4\ N\times 2\ m\\\\W=8\ J

So, the work done by the cart is 8 J.

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A surfer paddles out beyond the breaking surf to where waves are sinusoidal in shape, with crests 59.6 m apart. The surfer bobs
katrin [286]

Answer: y(x, y) = 2.14cos(6.04x - 8.29t)

wave speed (v) =1.38m/s,

wavelength ( λ) =59.6m

Amplitude (A) =2.14m

Wave number (k) =6.04

Angular frequency (ω) = 8.29rad/s

Explanation:

The wavelength is simply defined as the distance between 2 successive crest or trough.

From the question it has been stated that the crest are 59.6m apart, thus (λ) =59.6m.

The wave travels a total vertical distance of 4.28m, this simply implies that along the vertical axis of the sine graph, the wave traveled from maximum displacement to the positive y axis (+A) through the center (o) and to the maximum displacement to the negative axis (-A).

Meaning total vertical distance =2A where A=Amplitude

This amplitude is 4.28/2 = 2.14m

Wave number (k) =2π/(λ)

Where π=180°

Thus, k=2*180/59.6

K=360/59.6

K=6.04

To get the angular frequency of the wave(ω), we use the formulae above

(ω)=kv

Where v is the wave speed

v=vertical distance/time taken

v= 4.28/3.09= 1.31m/s

Thus

(ω)=kv=6.04 * 1.31 =8.29rad/s.

Equation of wave is below

y(x,t)=Acos(kx−ωt)

By slotting in the parameters we have that

y(x, y) = 2.14cos(6.04x - 8.29t)

Above is the mathematical equation that describes the wave.

3 0
3 years ago
During an automobile crash test, the average force exerted by a solid wall on a 1,900 kg car that hits the wall is measured to b
777dan777 [17]

Answer:

 u = 23.68 m/s

Explanation:

given,

mass of the car, m = 1900 Kg

Force exerted on the wall, F = 150,000 N

time of contact, t = 0.3 s

final speed of the car = 0 m/s

initial speed of the car = ?

we know,

Impulse is equal to change in momentum

J = m v- mu

J = 1900 x 0 - 1900 x (-u)

J = 1900 u

impulse is also equal to force into time

J = F x t

equating both equation of impulse

1900 u = F  x t

1900 u = 150000 x 0.3

1900 u = 45000

 u = 23.68 m/s

Speed of the car before collision is equal to 23.68 m/s

3 0
3 years ago
2. An object is dropped from rest. Calculate its velocity after 2.5s if it is dropped:
Alekssandra [29.7K]

Answer:

a=24.5 b=9.5

Explanation:

7 0
3 years ago
On a cello, the string with the largest linear density (1.44 x 10-2 kg/m) is the C string. This string produces a fundamental fr
Rus_ich [418]

Answer:

T=346.5N

Explanation:

From the question we are told that:

Density \rho=  (1.44 * 10^{-2} kg/m)

FrequencyF=93.0Hz

Lengthl=0.834m

Generally the equation for Frequency is mathematically given by

F=\frac{1}{2 l}sqrt{\frac{T}{\rho}}

Therefore

T=\rho(2 lF)^2

T= (1.44 * 10^{-2}*(2*0.834)(93.0))^2

T=346.5N

4 0
3 years ago
In which of these samples do the molecules mist likely have the least kinetic energy
KiRa [710]
Provide the examples again, no samples are presents.
8 0
3 years ago
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