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lubasha [3.4K]
3 years ago
11

Can someone please help me? If somebody pushes a cart with 4N of force and the cart moves a distance of 2 meters, how much work

did they do?
Physics
1 answer:
sergeinik [125]3 years ago
7 0

Answer:

Work done, W = 8 J

Explanation:

We have,

Force acting on the cart is 4 N

Cart covers a distance of 2 m

We need to find the work done by the cart. Work done by an object is given in terms of force and displacement. It can be given by :

W=Fd\\\\W=4\ N\times 2\ m\\\\W=8\ J

So, the work done by the cart is 8 J.

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False because the allocation rule of "first come-first served" promotes productive cooperation.
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A racecar accelerates uniformly from 18.5 mil to 46.1 m/s in 2.47 seconds.
laiz [17]

Answer:

<em>The acceleration of the racecar is</em> \mathbf{11.17~m/s^2}

Explanation:

<u>Uniformly Accelerated Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Following the definition above, the acceleration is defined as:

\displaystyle a=\frac{v_f-v_o}{t}

Where a is the constant acceleration, vo the initial speed, vf the final speed, and t the time.

The racecar goes from vo=18.5 m/s to vf=46.1 m/s in t=2.47 seconds, thus the acceleration is:

\displaystyle a=\frac{46.1-18.5}{2.47}

\displaystyle a=\frac{27.6}{2.47}

a = 11.17~m/s^2

The acceleration of the racecar is \mathbf{11.17~m/s^2}

5 0
3 years ago
You place an object 30.0 cm from a concave mirror of 15.0 cm focal length. The object is 1.8 cm tall. Find the image position an
Softa [21]

Answer:30 cm

Explanation:

Given

object distance u=30\ cm

focal length of concave mirror f=15\ cm

height of object h_o=1.8\ cm

Using mirror formula

\Rightarrow \frac{1}{v}+\frac{1}{u}=\frac{1}{f}

\Rightarrow \frac{1}{v}=\frac{1}{15}-\frac{1}{30}

\Rightarrow \frac{1}{v}=\frac{2-1}{30}

\Rightarrow v=30\ cm

and magnification is

\Rightarrow m=\frac{-v}{u}=\frac{h_i}{h_o}

\Rightarrow \frac{-30}{30}=\frac{h_i}{1.8}

\Rightarrow h_i=-1.8\ cm

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Position :image is formed at the spot where object is placed.

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A crate required 900 newtons (N) of force to lift. The crate was lifted by a forklift with an engine that provided 225 N of forc
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The mechanical advantage of the forklift is calculated to be 4.

<h3>MECHANICAL ADVANTAGE:</h3>
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M.A = Load/Effort

  • According to this question, a crate required 900 newtons (N) of force to lift. The crate was lifted by a forklift with an engine that provided 225 N of force. The mechanical advantage is calculated as follows:

M.A = 900N ÷ 225N

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