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Fofino [41]
3 years ago
9

The pail is rotated at a constant rate so it has the minimum speed at all points along its circular path. The water has mass m.

When the pail is at the bottom of the circle, what is the magnitude of the force exerted by the water on the bottom of the pail?
Physics
1 answer:
Alisiya [41]3 years ago
7 0

Answer:

Explanation:

The pail is rotated at a constant rate in vertical circular path  so it has the minimum speed at all points along its circular path . That means at top position the velocity is almost zero. In that case the centripetal force at top position will be provided by its weight or

mg = mv² / r ( r is radius of  vertical circular path )

v = √ rg

At the bottom position its velocity will be increased due to loss of potential energy

so 1/2 m V² = 1/2 m v² + mg x 2r  

V =√ 5 gr

If R be the reaction force at the bottom by bottom of pail

R - mg = mV² / r

R = mg +mV² / r

= mg + m x 5gr / r

R = 6mg

This is the magnitude of the force exerted by the water on the bottom of the pail .

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4 0
4 years ago
20. In a parallel RL circuit, 10 mA flows through the resistor and 4 mA flows through the inductor. What phase angle separates v
stellarik [79]

Answer:

Option D: 21.8 degrees

Explanation:

In a parallel RL circuit, the current in the resistor R and that in the inductor L are separated among themselves 90 degrees as illustrated in the attached image. In the image the current in the resistor is represented in orange, that of the inductor in blue, and the total current (vector addition of the previous two) is represented  in red, forming a certain angle (theta) with respect to the current in the resistor. The output voltage is the same as the input voltage as measured over the resistor R.

Therefore, the phase angle that separated output voltage and total current can be obtained using the fact that tan(phase angle) = \frac{I_l}{I_R} = \frac{x}{y} \frac{4}{10}, therefore the angle is the arctangent of 4/10:

arctang(\frac{4}{10} )= 21.801 degrees.

8 0
4 years ago
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The concrete slab of a basement is 11 m long, 8 m wide, and 0.20 m thick. During the winter, temperatures are nominally 17°C and
mina [271]

Answer:

\frac{dQ}{dt}= 4312 W

Explanation:

As we know that base of the slab is given as

A = 11 \times 8

A = 88 m^2

now we know that rate of heat transfer is given as

\frac{dQ}{dt} = \frac{kA}{x} (T_2 - T_1)

here we know that

k = 1.4 W/m k

Also we have

x =0.20

\frac{dQ}{dt} = \frac{1.4(88)}{0.20}(17 - 10)

\frac{dQ}{dt}= 4312 W

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3 years ago
The way to earn a college diploma is by?
Morgarella [4.7K]
Going to college and passing all your classes
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4 years ago
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A 1400 kg aircraft going 40 m/s collides with a 1500 kg aircraft that is parked and they stick together after the collision and
Leni [432]

Answer:

67.6 m

Explanation:

For this problem, we just need to analyze the motion of the two planes after the collision.

The two planes stick together and move with a velocity of

u = 19.3 m/s

The problem tells us that they skid until they stop: so, their final velocity is

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We also know that they skid for a time of

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Therefore, we can find their stopping distance using the following suvat equation

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And substituting, we find

s=(\frac{0+19.3}{2})(7)=67.6 m

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