Answer:
C 1055 04 cm
Step-by-step explanation:
We don't need to see the figure, since we know for sure the cone fits into the cylinder (smaller diameter and height).
So, we first need to calculate the volume of the cylinder, which is given by the formula:
VT = π * r² * h
VT = 3.14 * 5² * 16 = 3.14 * 400 = 1,256 cubic cm
Then we calculate the volume of the cone, which is given by:
VC = (π * r² * h)/3
VC = (3.14 * 4² * 12)/3 = (3.14 * 192)/3 = 200.96 cu cm
Then we calculate the void space left inside the cylinder by subtracting the volume of the cone from the volume of the cylinder:
NV = VT - VC = 1,256 - 200.96 = 1,055.04 cu cm
Answer:
2nd one from the left.
Step-by-step explanation:
it has the same angle measures.
A. You would start off by a rectangle in the middle, then you would place to squares on the bottom and top if the rectangle. After you've done that, you place two rectangles (Same size as the original) on both sides of the original rectangle. Finally you add a rectangle (Same size) to either ends of the secondary rectangles. It should look like this.
B. You would start off with a rectangle in the middle, then you would add 2 equilateral triangles to the top and bottom of the rectangle. After that, you Simply put 2 rectangles (Same size as the original) on both sides of the rectangle. It should look something like this.
C. To make a pyramid, it's actually quite simple. You would start off with a square in the middle, and then place equilateral triangles on ALL sides of the square. It should look something like this.
I hope this helped ^^
1. Check the drawing of the rhombus ABCD in the picture attached.
2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.
3. The diagonals:
i) bisect the angles so m(ODC)=60°/2=30°
ii) are perpendicular to each other, so m(DOC)=90°
4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.
5. By the pythagorean theorem,

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*

=

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