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Annette [7]
3 years ago
14

Which is equivalent to 5 × 9 × 8? 72 × 8 45 × 72 45 × 9 5 × 72

Mathematics
2 answers:
HACTEHA [7]3 years ago
8 0

Answer:

5 x 72

Step-by-step explanation:

Oliga [24]3 years ago
6 0

Answer:

5×72

ggggggggggggggggggg

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A school debate team has 4 girls and 6 boys. A total of 3 of the team members will be chosen to participate in the district deba
Varvara68 [4.7K]
The probability that 1 girl and 2 boys will be selected is given by:
P(1\ boy,\ 2\ girls)=\frac{4C1\times6C2}{10C3}=\frac{1}{2}
The correct answer choice is B. 1/2.
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What is n^3 divided by n?
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The answer is n^2. hope this helped :)
3 0
3 years ago
The student relations committee of a college consists of 2 administrators, 3 faculty members, and 5 students. Four administrator
Nana76 [90]

Step-by-step explanation:

4 administrator are eligible and  the student relations committee has only 2 administrator there are C (4,2) ways of choosing the administrators for the student relations committee

similarly for faculty  members  ways (8,3)       and  for students C (20,5)

the number of possible committee = 4!/2!2!  ×  8!/3!5!   ×20!/5!15!

                                                          = 6  ×56 ×15504

                                                          = 5,209,344

6 0
3 years ago
PLS ANSWER ILL MARK U BRAINLIEST
maxonik [38]

Given the length of the two diagonals of the kite, the area of kite ABDC is 33 squared centimeters.

<h3>What is the area of kite ABDC?</h3>

Formular for the area of a kite is expressed as;

A = pq/2

Where p and q are the two diagonals of the kite.

Given the data in the question;

  • Diagonal p = line BC = BM + MC = 3 + 3 = 6
  • Diagonal q = line AD = AM + MD
  • Line AM = ?
  • Line MD = ?

From the diagram, we can determine line AM and line MD using Pythagoras theorem.

c² = a² + b²

First, we find line AM

c² = a² + b²

5² = 3² + b²

25 = 9 + b²

b² = 25 - 9

b² = 16

b = √16

b = 4

Line AM = 4

Next, we determine Line MD

c² = a² + b²

(√58)² = 3² + b²

58 = 9 = b²

b² = 58 - 9

b² = 49

b = √49

b = 7

Line MD = 7

Now, we can find the area of the kite.

Diagonal p = BC = 6

Diagonal q = AD = AM + MD = 4 + 7 = 11

Area = pq/2

Area = [ 6 × 11 ]/2

Area = 66 / 2

Area = 33cm²

Given the length of the two diagonals of the kite, the area of kite ABDC is 33 squared centimeters.

Learn more about area of kite here: brainly.com/question/12286366

#SPJ1

5 0
1 year ago
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