<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Answer:
$12.60 is the new price!
Step-by-step explanation:
20 x 0.7 = 14
14 x 0.9 = 12.6
Hope this helped!
Send a picture so i can answer it
Answer:
area of trapezium: -
formula...
½(sum of parallel sides)×height=area
=>240=½(12+x)×12
=>240=(12+x)×6
=>240=60+6x
=>6x=240-60
=>6x=180
=>x=180/6
=>x=30cm
therefore, the value of x is 30 cm.
Step-by-step explanation:
hope it helps u
