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3 years ago

2 Points

Mathematics

1 answer:

Gnesinka [82]3 years ago

3 0

Answers are A, C, and D!

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If the initial amount of iodine-131 is 537 grams , how much is left after 10 days?

viktelen [127]

Answer:

225.78 grams

Step-by-step explanation:

To solve this question, we would be using the formula

P(t) = Po × 2^t/n

Where P(t) = Remaining amount after r hours

Po = Initial amount

t = Time

In the question,

Where P(t) = Remaining amount after r hours = unknown

Po = Initial amount = 537

t = Time = 10 days

P(t) = 537 × 2^(10/)

P(t) = 225.78 grams

Therefore, the amount of iodine-131 left after 10 days = 225.78 grams

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3 years ago

Solve for x. Round to the nearest tenth, if necessary. P 29° х Q -6.6 R

Margarita [4]

Answer:

The x in this question is 151 degrees

7 0

3 years ago

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Can someone please answer?

gtnhenbr [62]

Answer:

The answer is 24

Step-by-step explanation:

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3 years ago

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Twenty-five randomly selected students were asked the number of movies they watched the previous week. The results are as follow

guajiro [1.7K]

Answer:

a) x = 1.52

b) s = 1.16

Step-by-step explanation:

We have that:

5 students watched 0 movies.

9 students watched 1 movie.

5 students watched 2 movies.

5 students watched 3 movies.

1 student watched 4 movies.

(a) Find the sample mean x.

Sum divided by the number of students. So

$x = \frac{5*0 + 9*1 + 5*2 + 5*3 + 1*4}{5 + 9 + 5 + 5 + 1} = \frac{38}{25} = 1.52$

(b) Find the approximate sample standard deviation, s.

Standard deviation of the sample.

Square root of the sum of the squares of the values subtracted from the mean, divided by the sample size subtracted by 1. So

$s = \sqrt{\frac{5*(0-1.52)^2 + 9*(1-1.52)^2 + 5*(2-1.52)^2 + 5*(3-1.52)^2 + 1*(4-1.52)^2}{24}} = \sqrt{\frac{32.24}{24}} = 1.16$

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3 years ago

Show how you can solve the equation 3x=9 (i cant solve it im a pea brain)

faltersainse [42]

Answer:

divide both sides by 3

Step-by-step explanation:

so the answer should be x=3

6 0

3 years ago