All categories

2 years ago

Given below is the odd-number function. which of the following are equal to o(7)?

Mathematics

2 answers:

Sav [38]2 years ago

4 0

If this is a multiple choice question, try to see if -7 and 7 come up as a pair or just -7. I think it is -7.

sveta [45]2 years ago

4 0

We have to see the multiple-choice answers.

You might be interested in

i have 6 digits. One of my 3s is worth 300.000. The other is worth 1/10 as much. My 6 is worth 600.The rest of my digits are zer

motikmotik

The way you wrote the problem makes the answer 330,600. I think your decimals were meant to be commas. If I am wrong, please forgive me.

3 0

3 years ago

What is the solution to the equation −p − 13 = −4 /3 p + 2/3 ( 5p − 6 ) ?

jekas [21]

Answer:

The answer is p= 2 and 1/3

Step-by-step explanation:

This answer can be found using the order of operations to solve for p.

Start by distributing 2/3 by (5p-6)

add -4/3p to 10/3p equaling 6/3p or 2p

subtract 13 from both sides

-p= 2p - 7

p=2 and 1/3

3 0

2 years ago

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago

PLEASE HELP I DONT WANNA FAIL MY QUIZ!!!

Gwar [14]

Answer: 2.5 ft.

Step-by-step explanation: We know that the wall is 10ft and each poster is 1 1/4 ft, so subtract both posters from the wall, 10-2.5 = 7.5, then divide 7.5 by 3 since we need 3 lengths, and we get 2.5ft. So for x, it would be 2.5ft.

x=2.5

Hope this helps!

3 0

3 years ago

Read 2 more answers

What is the area of a triangle with base 18 meters and height<br>6 meters?

mash [69]

Answer:

27 meters

Step-by-step explanation:

a=1/2bh

a=1/2(18)(6)

a=27

6 0

3 years ago