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gulaghasi [49]
3 years ago
14

Write the point-slope form of the equation of the line through the given point with the given slope.

Mathematics
2 answers:
Marta_Voda [28]3 years ago
7 0

Answer:

1. y-4=4(x-1)

2. y-1=1(x+5)

3. y-1=\frac{1}{2}(x+4)

4. y+5=-\frac{4}{5}(x-5)

5. y-0=-\frac{1}{3}(x+1)

Step-by-step explanation:

∵ The equation of a line passes through (x_1, y_1) and (x_2, y_2) is,

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

We know that,

The slope of the line is,

m=\frac{y_2-y_1}{x_2-x_1}

\implies y-y_1=m(x-x_1)

Which is the point slope form of a line,

1. Thus, the equation of line passes through (1, 4) with slope 4 is,

y-4=4(x-1)

2. The equation of line passes through (-5, 1) and (-4, 2),

y-1=\frac{2-1}{-4+5}(x+5)

y-1=1(x+5)

3. The equation of line passes through (-4, 1) and (0, 2),

y-1=\frac{2-1}{0+4}(x+4)

y-1=\frac{1}{2}(x+4)

4. Now, two parallel lines having the same slope.

Thus, the slope of line parallel to y = -4/5x - 4 is, -4/5,

So, the equation of line passes through (5, -5) with slope -4/5 is,

y+5=-\frac{4}{5}(x-5)

5. If a line has slope m then the slope of perpendicular line is -\frac{1}{m}

Slope of line y = x + 3,

Slope of perpendicular line of y = x + 3 = -\frac{1}{3},

So, the equation of line passes through (-1, 0) with slope -\frac{1}{3},

y-0=-\frac{1}{3}(x+1)

IrinaVladis [17]3 years ago
5 0

Answer:

all steps in the picture above

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