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Luda [366]
3 years ago
7

Suppose the large number of auto accidents in a small town results in new legislation that requires all citizens of the town to

install new anti-lock brakes on their cars. These new brakes cut the time it takes a car to stop by 50%, allowing drivers to avoid collisions with other cars and pedestrians more easily.
The new brakes _______________ the probability that a vehicle will collide with another vehicle but also give drivers an incentive to drive more _____________, which could potentially ______________ the number of car accidents.
Mathematics
1 answer:
kati45 [8]3 years ago
3 0

Answer:

Step-by-step explanation:

The new brakes decrease the probability that a vehicle will collide with another vehicle. Because the anti-lock brakes cut the time it takes a car to stop by 50%, then total collision will be reduced.

But also give drivers an incentive to drive faster, which could potentially increase the number of car accidents.

Because drivers know that the new brakes cut the time it takes to stop and if they drive faster than before, maybe the new brakes won´t be able to reduce accidents and maybe collisions will increase.

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Answer: Choice D

b greater-than 3 and StartFraction 2 over 15 EndFraction

In other words,

b > 3 & 2/15

or

b > 3\frac{2}{15}\\\\

========================================================

Explanation:

Let's convert the mixed number 2 & 3/5 into an improper fraction.

We'll use the rule

a & b/c = (a*c + b)/c

In this case, a = 2, b = 3, c = 5

So,

a & b/c = (a*c + b)/c

2 & 3/5 = (2*5 + 3)/5

2 & 3/5 = (10 + 3)/5

2 & 3/5 = 13/5

The inequality 2 \frac{3}{5} < b - \frac{8}{15}\\\\ is the same as \frac{13}{5} < b - \frac{8}{15}\\\\

---------------------

Let's multiply both sides by 15 to clear out the fractions

\frac{13}{5} < b - \frac{8}{15}\\\\15*\frac{13}{5} < 15*\left(b - \frac{8}{15}\right)\\\\39 < 15b-8\\\\

---------------------

Now isolate the variable b

39 < 15b-8\\\\15b-8 > 39\\\\15b > 39+8\\\\15b > 47\\\\b > \frac{47}{15}\\\\b > \frac{45+2}{15}\\\\b > \frac{45}{15}+\frac{2}{15}\\\\b > 3+\frac{2}{15}\\\\b > 3\frac{2}{15}\\\\

Side note: Another way to go from 47/15 to 3 & 2/15 is to notice how

47/15 = 3 remainder 2

The 3 is the whole part while 2 helps form the fractional part. The denominator stays at 15 the whole time.

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