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3 years ago

The density of an object can be found using the formula below, where d is the density, m is the mass, and V is the volume.

Mathematics

1 answer:

Verizon [17]3 years ago

5 0

Answer:

it is A. 2.5 g/cm3

Step-by-step explanation:

d=m/v

d=32.25/12.9

d=2.5g/cm3

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(p²-pq + q²) ( 3p+ 3q)

RUDIKE [14]

Answer:

3p^3 + qp^2 - pq^2 + 3q^3

Step-by-step explanation:

(p²-pq + q²) ( 3p+ 3q)

3p^3 + 3qp^2 - 3qp^2 - 3pq^2 + 3pq^2 + 3q^3

3p^3 + qp^2 - pq^2 + 3q^3

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3 years ago

The graph shows the function f(x) = |x-h[ + k. What is

Olegator [25]

Answer:

K=-2.5

Step-by-step explanation:

because the line is in the middle of 2 and 3 and is below which means that it is negative

8 0

3 years ago

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The table represents the average daily price of a two-bedroom beachfront condo each month, with January represented as month 1,

ruslelena [56]

Answer:

y = - 9.1768x2 + 122.2567x + 14.9091

Step-by-step explanation:

Given the following :

Month (x) Daily Rental Price (y) 1 $154 2 $205 3 $266 4 $358 5 $403 6 $425 7 $437 8 $430 9 $381 10 $285 11 $211 12 $195

Using the online regression equation graphing tool ; The quadratic model obtained in the form,

y = Ax^2 + Bx + C is :

y = - 9.1768x2 + 122.2567x + 14.9091

Attached below is a picture of the quadratic regression curve.

7 0

3 years ago

An object at the top of a building with height 110 feet is thrown upward with an initial speed of 23 ft/s. Find its position z(t

alina1380 [7]

Answer:

Step-by-step explanation:

Given

Height of building is $h=110\ ft$

Initial upward velocity $u=23\ ft/s$

height of object is given by

$z(t)=ut+\frac{1}{2}gt^2$

but building is already at a height of 110 ft so z(t) must be given by

$Z(t)=ut+\frac{1}{2}(-g)t^2+110$

$Z(t)=23\times t-\frac{1}{2}\times 9.8\times t^2$

$Z(t)=-16t^2+23t+110$

Time when it hits is given by when Z(t)=0[/tex]

$-16t^2+23t+110=0$

$t=\frac{-23\pm \sqrt{(23)^2-4\times (-16)\times 110}}{2\times (-16)}$

$t=\frac{-23\pm 87}{-32}$

$t=3.43\ s$

6 0

3 years ago

How do you do this problem?

faust18 [17]

The volume of the original cylinder is

... V = π·r²·h

For r=1 and h=1, this is

... V = π·1²·1 = π

For the new cylinder, the volume is 1.089 times that amount.

... V = 1.089π = π·1.1²·(1-k)

... 1.089/1.21 = 1-k

... k = 1 - 1.089/1.21 = 1 - 0.9 = 0.1 = 10%

The appropriate choice is (B) 10.

7 0

3 years ago

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