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make me brainliest
Hello,
which principle?
f(x)=-x²+2x
==>f'(x)= -2x+2
You mean maybe this

f(x+h)=-(x+h)²+2(x+h)= -(x²+2hx+h²)+2x+2h
f(x)=-x²+2x
Answer: 26.8 feet
Step-by-step explanation:
In the figure attached you can see two right triangles triangle ABD and a triangle ACD.
You are located at point B and the other person at point C.
The approximate height of the lifeguard station is <em>x</em>.
Keep on mind that:

Therefore:
<em>For the triangle ABD</em>:
[EQUATION 1]
<em>For the triangle ACD:</em>
[EQUATION 2]
Solve from DC from [EQUATION 2]:

Substitute into [EQUATION 1] and solve for x:

≈26.8ft
The 82nd term for the sequence would be -4