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sasho [114]
3 years ago
10

Miguel draws △JKL with vertices J(−12, −1) , K(12, 9) , and L(12, −1) . Then he dilates the triangle with a scale factor of 6 to

create △J′K′L′. How are the areas of the triangles related?
Enter your answer in the box.
The area of △J′K′L′ is [__?__] times the area of △JKL.
Mathematics
1 answer:
Zina [86]3 years ago
3 0
Ik I'm late but for my homies in k12: 36
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For a quadrilateral to be a square, the diagonals must be ________________.
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Answer:

That bisect and are perpendicular

Step-by-step explanation:

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2 years ago
I don’t know what to do on here it’s really hard and I need help for the answer
Alla [95]
Ok so our original fraction is:
\frac{36 {x}^{12} }{6 {x}^{9} }
To simplify this fraction, look for instances where the values on the top and bottom can be reduced:

For example, 36 over 6 is the same as 6 over 1, so we can simplify the fraction so it is:
\frac{6 {x}^{12} }{ {x}^{9} }
We can also eliminate the denominator by dividing the nominator by x^9 so:
\frac{6 {x}^{12} }{ {x}^{9} }  \div  \frac{ {x}^{9} }{ {x}^{9} }
= 6 {x}^{3}
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Hope this helped
5 0
3 years ago
What is (−3.2)⋅1.7 multipluied
Natalka [10]

Answer:

-5.44

Step-by-step explanation:

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6 0
3 years ago
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The map of a mall is overlaid with a numeric
Veseljchak [2.6K]

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\sqrt{118}<em> or 10.8627805 </em>

Step-by-step explanation:

Start by taking the difference of each value of both points

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76+42=118

<u>Take the square root of this value </u>

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Step-by-step explanation:

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