Write this proof please

Mathematics

1 answer:

True [87]3 years ago

8 0

Answer:

Triangle HIK is congruent to triangle JGK

KI = KG (CPCT)

HK = JK (CPCT)

Angle HKG = angle JKI

Therefore triangle HKG is congruent to triangle JKI

GH = IJ (CPCT)

Hope this helps!

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The revenue, in dollars, that eMathInstruction makes off its videos in a given day depends on how many views they receive. If x

SCORPION-xisa [38]

Answer:

183590

Step-by-step explanation:

1/2(600)^2+6(600)-10

1/2(360000)+6(600)-10

180000+3600−10

183590

5 0

3 years ago

In the circle below, EG is a diameter and EF is tangent at E. Suppose mEF = 124°. Find the following. Does anyone know this?

Ludmilka [50]

Answer:

Step-by-step explanation:

If EG is a diameter, then arc EFG is a semicircle and its measure is 180. Arc FG then is 180 - 124 = 56. Since angle FEG is an inscribed angle and the arc it cuts off is arc FG, then the measure of the inscribed angle is half the measure of the arc it cuts off...so angle FEG is 28 degrees. Keep that in mind; we'll need it in a sec.

If HE is tangent to the circle at E, then angle HEG is a 90 degree angle. Adding that to angle FEG will give you angle FEH. Angle FEH = 90 + 28 = 118

8 0

3 years ago

Will Mark brainliest if answer both correctly / What is X= ? / conditional statement

harkovskaia [24]

The answer is for 1st question is “10.4” and for the second question “non of these choices are correct”.

Explanation:

For the 1st question:

tan = opposite / adjacent

tan 30 = x / 18

18 tan 30 = x

x = 10.4

For the 2nd question,
If a triangle as an angle of 90 degree, it is 100% a right triangle.

Hope it helps :), mark me brainliest please!

6 0

3 years ago

In the beginning of the study, a randomly selected group of 121 students scored an average of 252 words per minute on the readin

Alborosie

Answer:

Since the sample size is larger than 30, the cognitive psychologist can assume that the sampling distribution of M will be approximately normal.

Step-by-step explanation:

We use the central limit theorem to solve this question.

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a sample size larger than 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$