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Shkiper50 [21]
3 years ago
5

The probability is 0.6 that a calibration of a transducer in an electronic instrument conforms to specifications for the measure

ment system. Assume the calibration attempts are independent. What is the probability that at most three calibration attempts are required to meet the specifications for the measurement system?
Mathematics
1 answer:
allochka39001 [22]3 years ago
4 0
This fair seems like 3 autonomous occasions to me. At the end of the day, you do the adjustment and, on the off chance that it doesn't meet details, you do it once more. On the off chance that regardless it doesn't meet details, you do it a third time. At that point you quit, I figure, and attempt to make sense of why you can't get the darn thing right. 
In this way, in any case, you have a .6 possibility of getting the alignment right and a .4 chance you have to rehash it. The solution to your question is the likelihood you don't have three sequential disappointments, which is beneath: 
1 - .4 x .4 x .4 = 1 - .064, or 93.6%
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You wish to test whether the number of fouls called in regular season games is different than during the NCAA tournament. The me
kolezko [41]

Answer:

the lower value of the interval = 35.26

Step-by-step explanation:

The mean number is u = 40.1

n = 16

the mean number called x is 38.1

the standard deviation = 5.8

given a 95% Confidence Interval

The lower value of the confidence interval is?

<u>solution</u>

There is a infinite population and the standard deviation of the population is known,

the below formula is used for determining an estimate of the confidence limits of the population mean, i.e.

x ± ( zₐσ)/ √n

For a 95% confidence level, the value of za is taken from the confidence interval table = 1.96.

the confidence limits of the population=

x ± ( zₐσ)/ √n

38.1 ± (1.96*5.8)/ √16

38.1 ± 11.368/4

38.1 ± 2.842

40.942 or 35.258

 Thus, the 95% confidence limits are 40.942 or 35.258

this prediction is made with confidence that it will be correct nine five times out of 100.

finally, the lower value of the interval = 35.26

7 0
4 years ago
Whats 9 divided by 1/3 ( show work please thx !)
Vsevolod [243]
It's 27. When dividing fractions, you multiply the first number by the reciprocal of the second number. The reciprocal of 1/3 is 3/1. 9x3/1=27
6 0
3 years ago
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What is 7/9 divided by 1/3
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Answer:

{ \tt{ =  \frac{7}{9}  \div  \frac{1 }{3} }} \\  = { \bf{ \frac{7}{9}  \times  \frac{3}{1} }} \\  =  \frac{7}{3}

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Answer:

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Step-by-step explanation:

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