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andriy [413]
3 years ago
12

A publisher requires 2⁄3 of a page of advertisements for every 5 pages in a magazine. If a magazine has 98 pages, to the nearest

whole page, how many pages of the magazine are advertisements?
Mathematics
1 answer:
rjkz [21]3 years ago
3 0

Let x be the number of pages of advertisements.

Write a proportion from the table:

\dfrac{2}{3} of a page of advertisment - 5 pages in a magazine

x pages of advertisment - 98 pages in a magazine,

then

\dfrac{\dfrac{2}{3}}{x}=\dfrac{5}{98}.

Find x:

x=\dfrac{\dfrac{2}{3}\cdot 98}{5}=\dfrac{196}{15}=13\dfrac{1}{13}.

Answer: 13 whole pages and \dfrac{1}{13} of 14th page are advertisments, so 14 pages contain advertisments.

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kramer

Answer:

what do we have to do

Step-by-step explanation:

8 0
4 years ago
Tia owns a fruit shop and is selling a fresh lot of apples and oranges. She wants the ratio of apples to oranges sold to be 4 to
____ [38]

Answer: 32 apples

Step-by-step explanation:

The ratio of apples to oranges sold is given as 4 to 2. Since Tia wants to sell a total of 48 apples and oranges, the number of apples that she should sell would be:

= 4/(4+2) × 48

= 4/6 × 48

= 32

Therefore, he should sell 32 apples.

7 0
3 years ago
Gary jogs 2/3 of a mile in 1/3 of an hour. how many mipes can he jog in 1 hour?
cricket20 [7]
2 miles.
This is because 2/3 times 3 equals 2.
8 0
3 years ago
Hi please help me thanksss<br>pls provide workings too thanks :)​
anygoal [31]

Step-by-step explanation:

Search for questions & chapters

Class 11

>>Maths

>>Trigonometric Functions

>>Trigonometric Equations

>>Solve for x: sin x + sin 2x...

Question

Bookmark

Solve for x:sinx+sin2x+sin3x=cosx+cos2x+cos3x in the interval 0≤x≤2π.

Medium

Solution

verified

Verified by Toppr

We write the given equation as

(sinx+sin3x)+sin2x=(cosx+cos3x)+cos2x

or 2sin2xcosx+sin2x=2cos2xcosx+cos2x

or sin2x(2cosx+1)=cos2x(2cosx+1)

or (sin2x−cos2x)(2cosx+1)=0

∴sin2x−cos2x=0 or 2cosx+1=0

If sin2x−cos2x=0, then tan2x=1,

Hence 2x=nπ+π/4

or x=(4n+1)

8

π

.(1)

If 2cosx+1=0, then cosx=−1/2 (2)

∴x=2nπ±

3

2π

or x=

3

6n±2

π

We seek values of x in the interval 0≤x≤2π

In this interval (1) gives

x=π/8,5π/8,9π/8,13π/8. (n=0,1,2,3)

and (2) gives x=2π/3,4π/3. (for n=0,1)

Thus we get the answer

x=π/8,5π/8,2π/3,9π/8,4π/3,13π/8.

4 0
3 years ago
Place the following temperatures in order from coldest to hottest: -8°C, 10°C, -5°F, 40°F
vova2212 [387]
-5f, -8c, 40f, 10c happy math..ing
6 0
3 years ago
Read 2 more answers
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