3 years ago

Slope 5 and (2,3) in point slope form and explain please.

Mathematics

1 answer:

PIT_PIT [208]3 years ago

3 0

Answer:

$y - 3 = 5( x- 2)$

Step-by-step explanation:

The point slope form of a line is the form $y-y_1 = m(x-x_1)$ where m is the slope and $(x_1,y_1)$ is a point on the line.

Here the slope is 5 and the point is (2,3).

Substitute and you'll have:

$y - 3 = 5( x- 2)$

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Yuri thinks that 3/4 is a root of the following function. q(x) = 6x3 + 19x2 – 15x – 28 Explain to Yuri why 3/4 cannot be a root.

k0ka [10]

Answer:

Yuri is not correct.

Step-by-step explanation:

Given expression is q(x) = 6x³ + 19x² - 15x - 28

If 'a' is a root of the given function, then by substituting x = a in the expression, q(a) = 0

Similarly, for x = $\frac{3}{4}$ ,

$q(\frac{3}{4})=6(\frac{3}{4})^3+19(\frac{3}{4})^2-15(\frac{3}{4})-28$

= $6(\frac{27}{64})+19(\frac{9}{16})-15(\frac{3}{4})-28$

= $(\frac{162}{64})+(\frac{171}{16})-(\frac{45}{4})-28$

= $(\frac{162}{64})+(\frac{684}{64})-(\frac{720}{64})-\frac{1792}{64}$

= $-\frac{1666}{64}$

= $-\frac{833}{32}$ ≠ 0

Therefore, Yuri is not correct. x = $\frac{3}{4}$ can not be a root of the given expression.

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Step-by-step explanation:

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