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pickupchik [31]
3 years ago
9

Luis choosing one card from the deck then choosing a second card without replacing the first. Is this independent or dependent

Mathematics
1 answer:
ElenaW [278]3 years ago
3 0

Luis choosing one card from the deck then choosing a second card without replacing the first is a dependent event.

Step-by-step explanation:

Lets define independent and dependent events first.

<u>Independent events:</u>

The events are said to be independent if the probability of occurrence of one event doesn't affect the probability of second event.

<u>Dependent events:</u>

The events in which the probability of occurrence of one event affects the second event's probability of occurrence, are called dependent events.

Now,

When a card is drawn from a deck of cards and NOT replaced, it makes the second event's probability depend on first event as the sample space for second event changes due to the first event.

Hence,

Luis choosing one card from the deck then choosing a second card without replacing the first is a dependent event.

Keywords: Probability, dependent events

Learn more about probability at:

  • brainly.com/question/10666510
  • brainly.com/question/10699220

#LearnwithBrainly

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4 years ago
Mrs. Welch and her 5 children are shopping at a local grocery store. Each of the children will be allowed to select one box of c
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<h3>Answer:  462</h3>

==================================================

Explanation:

Let's call the children A, B, C, D, E for the sake of simplicity. Also, let's have the children select in alphabetical order.

  • Child A has 11 choices to pick from.
  • Child B has 10 choices to pick from
  • Child C has 9 choices to pick from
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We started at 11 and counted down by 1 until we had all the children selecting.

Multiply out these values: 11*10*9*8*7 = 55440

There are 55440 different permutations possible. If order mattered, then we would stop here. However, order does not matter because the cereals aren't ranked and their position doesn't matter. All that matters is what fills the grocery cart. In other words, imagine the kids jumbling up the boxes as they push around the cart, so the order would be irrelevant.

Consider a group of 5 items. There are 5! = 5*4*3*2*1 = 120 different ways to arrange the five items in this group. So for any 5 cereals picked, there are 120 ways to order them. But again, order doesn't matter, so we have to correct for this over-counting. We do this by dividing by 120

55440/120 = 462

------------------

If you want to use a formula, then plug n = 11 and r = 5 into the combination formula below and simplify.

n C r = (n!)/(r!(n-r)!)

11 C 5 = (11!)/(5!*(11-5)!)

11 C 5 = (11!)/(5!*6!)

11 C 5 = (11*10*9*8*7*6!)/(5!*6!)

11 C 5 = (11*10*9*8*7)/(5!)

11 C 5 = (11*10*9*8*7)/(5*4*3*2*1)

11 C 5 = 55440/120

11 C 5 = 462

We get the same answer.

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