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Tcecarenko [31]
3 years ago
12

How do i do this ? I am so confused

Mathematics
1 answer:
Elanso [62]3 years ago
3 0
Add all of the statistics together, divide 5 by that total, then multiply that by 100.

(5 divided by 26) (which is the total) to get ).192 times 100.

The final answer is 19.2%
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Marcella's house cost $120 000. she paid 20 percent down payment and then borrowed the rest at 6.5 percent for 20 years. if she
chubhunter [2.5K]

Answer:

20% of 120,000 is 24,000 so 120,000-24,000 is 96,000

Now if she pays 7.46 for every 1000 she will have to repay 716.16 over 20 years.

Step-by-step explanation:


5 0
3 years ago
Read 2 more answers
What is the radius of a basketball with a diameter of 22 inches?
Ghella [55]

Answer:

11

Step-by-step explanation:The radius will always be half of the diameter therefore it will be 11

7 0
3 years ago
A square has side lengths of (4x+5) inches.Write an expression to represent the perimeter of the rectangle.Then find the perimet
Marat540 [252]

Answer:

68 inches

Step-by-step explanation:

P = 2 (L + W)

P = 2(4x+5 + 4x+5)

P = 2(8x + 10)

P = 16x + 20

If x= 3

P = 16(3) + 20

P = 48 + 20

P = 68 inches

3 0
3 years ago
Solve this A tourist starts off from town A and travels for 50km on a bearing of N80°W to town B.At town B ,he continues for ano
VLD [36.1K]

Answer:

The point C is 12.68 km away from the point A on a bearing of S23.23°W.

Step-by-step explanation:

Given that AB is 50 km and BC is 40 km as shown in the figure.

From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|

=|50 sin 80° - 40 cos 20°|=11.65 km

The length of y-component of AC = |AB cos 80° - BC sin 20°|

=|50 cos 80° - 40 sin 20°|= 5 km

tan\theta= 5/11.65

\theta=23.23°

AC= \sqrt{5^2+11.65^2}=12.68 km

Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.

8 0
2 years ago
How can you tell that the inequality 3t+1> 3t + 2
lutik1710 [3]

Answer:

see below

Step-by-step explanation:

3t+1> 3t + 2

Subtract 3t from each side

1>2

This is never true so there is no solution

Since the variable terms are the same, we only have to look at the constants

6 0
3 years ago
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