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adell [148]
3 years ago
11

Can u help me answer this I’m so stuck

Mathematics
1 answer:
Slav-nsk [51]3 years ago
6 0

Answer:

I learned a great formula for repeating decimals.

OK! Let's get started. For each decimal spot that is recurring, it is put over a 9, rather than a 10.

In your case, 0.142 would be 142 over 3 9s.

142/999 cannot be simplified.

Therefore, 142/999 is our answer.

Since the repentant is over only one digit, we have to solve another way.

We can represent it as "x"

10x = 5.66.... - x = 0.56.....=5.1

9x = 51/10

51/10/9 = 51/90 = 17/30 as our answer.

We can solve this next one the same way:

100x = 3.44444 - x  = 3.41

999x = 341/100

341/100/999 = 31/900 as our answer.

Now! 1.52 can be solved the same way.

In doing so, we achieve the answer 151/99 as our answer

This one can be done the same way as well. I'll give you the answer, but next time try to solve it for yourself!

179/495 is our answer.

Now, you asked for 0.004 as a fraction.

That is equivalent to 4/999 as our answer.

Note: This is because each 0 can be counted as a 9, increasing in order. (i.e., over 100 is over 99 over 1000 is over 999 over 10 9)

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The coordinates of other endpoint S is (3, 2)

<h3><u>Solution:</u></h3>

Given that midpoint of RS is M

Given endpoint R(23, 14) and midpoint M(13, 8)

To find: coordinates of the other endpoint S

<em><u>The formula for midpoint is given as:</u></em>

For a line containing containing two points (x_1, y_1) and (x_2, y_2) midpoint is given as:

m(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Here in this problem,

m(x, y) = (13, 8)

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Substituting the given values in above formula, we get

(13,8)=\left(\frac{23+x_{2}}{2}, \frac{14+y_{2}}{2}\right)

Comparing both the sides we get,

\begin{aligned}&13=\frac{23+x_{2}}{2} \text { and } 8=\frac{14+y_{2}}{2}\\\\&26=23+x_{2} \text { and } 16=14+y_{2}\\\\&x_{2}=3 \text { and } y_{2}=2\end{aligned}

Thus the coordinates of other endpoint S is (3, 2)

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Step-by-step explanation:

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Step-by-step explanation:

Here is the complete question:

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