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zvonat [6]
3 years ago
13

F(x)=(x-2)/(x+4) find the domain

Mathematics
1 answer:
Lunna [17]3 years ago
3 0
<span>(<span><span>−∞</span>,4</span>)</span>∪<span>(<span>4,∞</span>)</span>,<span>{<span>x|x≠4</span><span>}</span></span>
You might be interested in
Which expressions are equivalent?
trapecia [35]

Only 3(a−b) and 3a−3b are equivalent

Further explanation:

We have to evaluate each expression to evaluate if the expressions are equivalent or not.

So,

<u>For 3(a−b)</u>

3(a-b)\\Distributing\ 3\ in\ bracket\\3.a-3.b\\=3a-3b

As we can see that 3(a-b) results in 3a-3b so these are equivalent

<u>For 2a(2+b)</u>

2a(2+b)\\Distributing\ 2a\\2a.2+2a.b\\=4a+2ab

As we can see that 2a(2+b) doesn't result in 4ab so these are not equivalent

Hence,

Only 3(a−b) and 3a−3b are equivalent

Keywords: Equivalent expression, Polynomials

Learn more about polynomials at:

  • brainly.com/question/4824362
  • brainly.com/question/4847829

#LearnwithBrainly

3 0
3 years ago
What is the volume (in cubic units) of a sphere with a radius of 6 units? Assume that π = 3.14 and round your answer to the near
abruzzese [7]

Answer: 904.32  cubic units.

Step-by-step explanation:

The formula for a sphere's volume is V = V = \frac{4}{3}\pi r^{3} \\

Substitute pi for 3.14 and radius for 6. 6^3 = 216

\\V = \frac{4}{3}\ (3.14)( 216) \\\\

Multiply them together, the answer is 904.32  cubic units.

8 0
3 years ago
What is 10⁰ + 10¹ + 10² equal to
Setler [38]
10^0 = 1

10^1 = 10

10^2 = 100

100 + 10 + 1 = 111
6 0
3 years ago
Read 2 more answers
How to find components of a vector given magnitude and angle?
Zanzabum
<span>1. Find the magnitude and direction angle of the vector.
2. Find the component form of the vector given its magnitude and the angle it makes with the positive x-axis.
<span>3. Find the component form of the sum of two vectors with the given direction angles.</span></span>
3 0
3 years ago
Can someone help me and explain? I will mark brainlest. ♡
Sedbober [7]

Answer:

p'(4) = -3

q'(8) = \frac{1}{4}\\

Step-by-step explanation:

For p'(4):

p(x) = f(x)g(x) \\ p'(x) = \frac{d}{dx}(f(x)g(x)) \\ p'(x) = f'(x)g(x) +f(x)g'(x)

p'(4) = f'(4)g(4) + f(4)g'(4) \\ p'(4) = (-1)(3) +(7)(0) \\ p'(4) = -3

For q'(8):

q(x) = \frac{f(x)}{g(x)} \\ q'(x)= \frac{d}{dx}(\frac{f(x)}{g(x)}) \\ q'(x) = \frac{f'(x)g(x) -f(x)g'(x)}{{g(x)}^2}

q'(8) = \frac{f'(8)g(8) -f(8)g'(8)}{{g(8)}^2} \\ q'(8) = \frac{(2)(2) -(6)(\frac{1}{2})}{{2}^2} \\ q'(8) = \frac{4 -3}{4} \\ q'(8) = \frac{1}{4}

4 0
3 years ago
Read 2 more answers
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