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crimeas [40]
3 years ago
7

What is the expanded form of the decimal 8542.53? A) (8 x 100) + (5 x 10) + (4 x 1) + (2 x 1 10 ) B) (8 x 1000) + (4 x 10) + (2

x 1) + (3 x 1 10 ) + (5 x 1 100 ) C) (8 x 1000) + (5 x 100) + (4 x 10) + (2 x 1) + (3 x 1 10 ) + (5 x 1 100 ) Eliminate D) (8 x 1000) + (5 x 100) + (4 x 10) + (2 x 1) + (5 x 1 10 ) + (3 x 1 100 )
Mathematics
2 answers:
Feliz [49]3 years ago
8 0
It’s D mark brainliest
ahrayia [7]3 years ago
6 0

Answer:

it’s D

Step-by-step explanation:

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City R has a temperature of -2 degrees. City S has a temperature of -6 degrees. Write an inequality to compare the temperatures
elena-s [515]

Answer:

  -2 > -6  . . .   or  . . .  R > S

Step-by-step explanation:

If you plot the temperatures of the two cities on a number line, you see that the temperature for City R is plotted to the right of the temperature for City S. This means the temperature of City S is less than that of City R.

If your inequality relates cities:

  S < R   or   R > S

If your inequality relates temperatures:

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Answer:

i think it was about 5000.

Step-by-step explanation:

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3 years ago
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To get the *percent increase* from week 1 to week 2, we calculate the change in distance from week 1 to week 2 (13.5 - 12.5 = 1 mile) over the week 1 distance (12.5 miles). Doing that, we find that Matthew increased his distance by

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We’re given that he’ll increase his distance by the same percentage from week 2 to 3, so to find his week 3 distance, we can find 8% of the week 2 distance and add that on. 8% of 13.5 miles is 0.08 x 13.5 = 1.08 miles, so by week 3, he’ll be running 13.5 + 1.08 = 14.58 miles.
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If I had 6 dollar bill to spent and I buy a chip for 2 dollars and an icecream sandwich box for 3 dollars would I have enough mo
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Answer:

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Step-by-step explanation:

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The area of a rectangle is 27 m^2 , and the length of the rectangle is 3 m less than twice the width. Find the dimensions of the
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Let L be the length of the rectangle and W be the width. In the problem it is given that L=2W-3. It is also given that the area LW=27. Substituting in the length in terms of width, we have W(2W-3)=27 \\ 2W^2-3W-27=0 \\ (2W-9)(W+3)=0. Using the zero product property, 2W-9=0 \text{ or } W+3=0. Solving these we get the width W=4.5 \text{ or } -3. However, it doesn't make sense for the width to be negative, so the width must be \boxed{4.5 \text{ m}}. From that we can tell the length L=2(4.5)-3=\boxed{6 \text{ m}}. 
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