Explain how you know the values of the digitsin the number 58
1 answer:
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Answer:
x = 1/2 or 2
Step-by-step explanation:
You can factor this as ...
2x^2 -4x -x +2 = 0 . . . rewrite the middle term to enable factoring
2x(x -2) -1(x -2) = 0 . . . . factor by grouping
(2x -1)(x -2) = 0 . . . . factor out (x -2)
x = 1/2, 2 . . . . . . values of x that make the factors zero
The first step for solving this equation is to determine the defined range.
, x ≠ 1
Remember that when the denominators of both fractions are the same,, you need to set the numerators equal. This will look like the following:
= 5
Take the root of both sides of the equation and remember to use both positive and negative roots.
x +/-![\sqrt[4]{5}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B5%7D)
Separate the solutions.
x = , x ≠ 1
x = -
Check if the solution is in the defined range.
x =
x = -
This means that the final solution to your question are the following:
x =
x = -
Let me know if you have any further questions.
:)
Remember that when the denominators of both fractions are the same,, you need to set the numerators equal. This will look like the following:
Take the root of both sides of the equation and remember to use both positive and negative roots.
x +/-
Separate the solutions.
x =
x = -
Check if the solution is in the defined range.
x =
x = -
This means that the final solution to your question are the following:
x =
x = -
Let me know if you have any further questions.
:)