QUICK, BRAINLIEST FOR 1ST ANSWER. 14.5 is incorrect!

Mathematics

1 answer:

ra1l [238]3 years ago

4 0

To get the *percent increase* from week 1 to week 2, we calculate the change in distance from week 1 to week 2 (13.5 - 12.5 = 1 mile) over the week 1 distance (12.5 miles). Doing that, we find that Matthew increased his distance by

1/12.5 = 0.08, or 8%

We’re given that he’ll increase his distance by the same percentage from week 2 to 3, so to find his week 3 distance, we can find 8% of the week 2 distance and add that on. 8% of 13.5 miles is 0.08 x 13.5 = 1.08 miles, so by week 3, he’ll be running 13.5 + 1.08 = 14.58 miles.

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Juli2301 [7.4K]

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a) P(X =16 ) = 0.1853

b) $P(X \leq 12)$ = 0.0684

Step-by-step explanation:

GIVEN DATA:

n = 16

p = 0.90

from relation given probabllity can be solve

$P(X) = ^nC_x * p^x * ( 1 - p)^{n-x}$

$P(X =16 ) = ^{16}C_{16} * 0.90^x * ( 1 - 0.90)^{16-16}$

P(X =16 ) = 0.1853

b) $P(X \leq 12) = 1 - P(X \geq 13)$

= 1 - [ P(X = 13) +P(X = 14) +P(X = 15) +P(X = 16) ]

$= 1 - [ ^{16}C_{13} * 0.90^{13} * (1 - 0.90)^3 +^{16}C_{14} * 0.90^{14} * (1 - 0.90)^2 +^{16}C_{15} * 0.90^{15} * (1 - 0.90)^1 +^{16}C_{16} * 0.90^{16} * (1 - 0.90)^0 ]$