Well, it is a good and interesting question
Such areas could be calculated in a single shoot and also by dividing the whole shape into other shapes and the total area would be the sum of these areas
I prefer the way of a single shoot ...
The figure represents a trapezoid:
its lower base = 21 units
its upper base = 12 units
the normal height between them = 8 units
NOW
The area of a trapezoid = [(sum of bases' lengths) ÷ 2] * height
= [(12 + 21) ÷ 2] * 8 = 132 sq units
Hope that helps
Answer:
x² + y² + 2x + 8y − 47 = 0 B. x²+y² − 2x − 8y
Step-by-step explanation:
The problem can be solved step by step, if we know certain basic rules of summation. Following rules assume summation limits are identical.
Armed with the above rules, we can split up the summation into simple terms:
=> (a)
f(x)=28n-n^2=> f'(x)=28-2n
=> at f'(x)=0 => x=14
Since f''(x)=-2 <0 therefore f(14) is a maximum
(b)
f(x) is a maximum when n=14
(c)
the maximum value of f(x) is f(14)=196
Answer:
its OX= -9
Step-by-step explanation:
Answer: 4/1
Step-by-step explanation:
Rise over run. Starting at 1 on the y axis this line moves up 4 and over (right) 1 before it hits 1 on the x axis.