We can classify the system by seeing if it’s consistent and independent. So that’s how you would classify the system.
Hopefully this helps!
(3,-1)
Use the V.L.T (Vertical Line Test) and plot the graph points, if you can draw a straight line through any points it cannot be a function.
The answer should be <span>−<span><span>15<span>a^6</span></span><span>b^5</span></span></span>+<span><span>12a</span><span>b^<span>2
Hope I helped</span></span></span>
The answer is 4.782, so yes maria is correct:-)
Answer/Step-by-step explanation:
Let's solve your equation step-by-step.
4−(2y+5)=3(1−4y)
Step 1: Simplify both sides of the equation.
4−(2y+5)=3(1−4y)
4+−1(2y+5)=3(1−4y)(Distribute the Negative Sign)
4+−1(2y)+(−1)(5)=3(1−4y)
4+−2y+−5=3(1−4y)
4+−2y+−5=(3)(1)+(3)(−4y)(Distribute)
4+−2y+−5=3+−12y
(−2y)+(4+−5)=−12y+3(Combine Like Terms)
−2y+−1=−12y+3
−2y−1=−12y+3
Step 2: Add 12y to both sides.
−2y−1+12y=−12y+3+12y
10y−1=3
Step 3: Add 1 to both sides.
10y−1+1=3+1
10y=4
Step 4: Divide both sides by 10.
10y
10
=
4
10
y=
2
5
Answer:
y=
2/5
yw
