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3 years ago

A store advertise 15% off an item that regularly sells for 300$. What is the sale price of the item

Mathematics

2 answers:

erik [133]3 years ago

7 0

Answer:

255

Step-by-step explanation:

(1-15%)a=300

a=255

svlad2 [7]3 years ago

5 0

Answer:255

Step-by-step explanation: 15% is 0.15. So to find what 15% of 300 is, you do 300 x 0.15. Which is 45. So 300-45=255.

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Simplify. 1/4y+1 1/2+2−1 3/4y−1/2

Ratling [72]

Your final answer for this question is -3(y-2)/2. Hope this helps.

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3 years ago

Read 2 more answers

A “stick” object of height 10 cm is standing in front of a point X–ray source at a distance of 50 cm from the source. The detect

blagie [28]

Answer:

40 cm.

Step-by-step explanation:

Given,

height of the object = 10 cm

Distance of the object from the X-ray= 50 cm

Distance of detector from the source = 2 m = 200 cm

Height of the image, h = ?

Now,

$\tan \theta = \frac{P}{B}$

$\tan \theta = \frac{10}{50}$

$\tan \theta = \frac{1}{5}$

Again applying

$\tan \theta = \frac{P}{B}$

$\frac{1}{5} = \frac{h}{200}$

h = 40 cm

Hence, height of the image is equal to 40 cm.

6 0

3 years ago

A particular variety of watermelon weighs on average 20.4 pounds with a standard deviation of 1.23 pounds. Consider the sample m

love history [14]

Answer:

a) The expected value of the sample mean weight is 20.4 pounds.

b)The standard deviation of the sample mean weight is 0.123.

c) There is a 14.46% probability the sample mean weight will be less than 20.27.

d) This value is $c = 20.6153$ .

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A particular variety of watermelon weighs on average 20.4 pounds with a standard deviation of 1.23 pounds. This means that $\mu = 20.4, \sigma = 1.23$

Consider the sample mean weight of 100 watermelons of this variety. This means that $n = 100$ .

a. What is the expected value of the sample mean weight? Give an exact answer.

By the Central Limit Theorem, it is the same as the mean of the population. So the expected value of the sample mean weight is 20.4 pounds.

b. What is the standard deviation of the sample mean weight? Give your answer to four decimal places.

By the Central Limit Theorem, that is:

$s = \frac{\sigma}{\sqrt{n}} = \frac{1.23}{\sqrt{100}} = 0.123$

The standard deviation of the sample mean weight is 0.123.

c. What is the approximate probability the sample mean weight will be less than 20.27?

This is the pvalue of Z when $X = 20.27$ .

Since we are working with the sample mean, we use $s$ instead of $\sigma$ in the Z score formula

$Z = \frac{X - \mu}{s}$

$Z = \frac{20.27 - 20.4}{0.123}$

$Z = -1.06$

$Z = -1.06$ has a pvalue of 0.1446.

This means that there is a 14.46% probability the sample mean weight will be less than 20.27.

d. What is the value c such that the approximate probability the sample mean will be less than c is 0.96?

This is the value of $X = c$ that is in the 96th percentile, that is, it's Z score has a pvalue 0.96.

So we use $Z = 1.75$

$Z = \frac{X - \mu}{s}$

$1.75 = \frac{c - 20.4}{0.123}$

$c - 20.4 = 0.123*1.75$

$c = 20.6153$

This value is $c = 20.6153$ .

6 0

2 years ago

A hammer is 1 foot long a car is 15 feet long and shovel is 4 feet long which statement is correct? Choose all that apply’s

Arturiano [62]

Answer:

Tationia Rolon

Step-by-step explanation:

Here

3 0

3 years ago

The table below shows the heights of several books. Jean stacks a dictionary on top of her novel. How high is the stack of the t

aev [14]

Answer:

The height of the stack = $5\frac{1}{4}$ in

Explanation:

We are given that Jean stacks a dictionary on top of a novel.

This means that the total height of the stack will be equal to the height of the dictionary added to the height of the novel.

From the givens, we have:

height of dictionary = $4\frac{1}{2}$ in

height of novel = $\frac{3}{4}$ in

Now, adding the two height, we will have:

Total height of stack = height of novel + height of dictionary

Total height of stack = $\frac{3}{4}+4 \frac{1}{2} = \frac{3}{4}+ \frac{18}{4}= \frac{21}{4}=5 \frac{1}{4}$ in

Hope this helps :)

6 0

3 years ago