Time-and-a-half doesn't make enough sense to answer the question. If you fix it, or comment below the correction I will gladly help.
Answer: The equation parallel to the line is y=3x+8
Step-by-step explanation: Parallel lines have the same gradients, wr have a gradient for the above line which 3. The standard formula for the linear equation is y=mx+c
We have to calculate c since we have x and y.
y=mx+c
5= 3(-1)+c
c=8
The equation become y=3x+8
We have that
<span>triangle ABC
where
A(-5, 5), B(1, 1), and C(3, 4) are the vertices
using a graph tool
see the attached figure
the hypotenuse is the segment AC
find the equation of the line AC
</span>A(-5, 5) C(3, 4)
<span>
step 1
find the slope m
m=(y2-y1)/(x2-x1)-----> m=</span>(4-5)/(3+5)-----> m=-1/8
step 2
with C(3,4) and m=-1/8
find the equation of a line
y-y1=m*(x-x1)-----> y-4=(-1/8)*(x-3)----> y=(-1/8)*x+(3/8)+4
y=(-1/8)*x+(3/8)+4----> multiply by 8----> 8y=-x+3+32
8y=-x+35
the standard form is Ax+By=C
so
x+8y=35
A=1
B=8
C=35
the answer isx+8y=35
You didn’t even post a diagram
which of the following diagram represent a relation that is not a function
Answer:
-70
Step-by-step explanation: