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monitta
3 years ago
6

3x+y-2z=22 x+5y+z=4 x=-3z

Mathematics
1 answer:
Ad libitum [116K]3 years ago
4 0
x = 6 ; y = 0 ; z = -2

3x  +   y  - 2z = 22   ⇒  3(6) + 0 -2(-2) = 22 ⇒ 18 + 4 = 22 ⇒ 22 = 22
  x  + 5y  + z =  4     ⇒   6 + 5(0) + (-2) = 4  ⇒  6 - 2 = 4 ⇒ 4 = 4
  x = -3z

3(-3z) + y - 2z = 22
-9z + y - 2z = 22
y - 11z = 22
y = 22 + 11z

x + 5y + z = 4
-3z + 5(22 + 11z) + z = 4
-2z + 110 + 55z = 4
53z = 4 - 110
53z = -106
z = -106/53
z = -2

x = -3(z)
x = -3(-2)
x = 6

y = 22 + 11z
y = 22 + 11(-2)
y = 22 - 22
y = 0
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<h3>How to find the production level that'll maximize profit?</h3>

The cost function, C(x) is given by 12000 + 400x − 2.6x² + 0.004x³ while the demand function, P(x) is given by 1600 − 8x.

Next, we would differentiate the cost function, C(x) to derive the marginal cost:

C(x) = 12000 + 400x − 2.6x² + 0.004x³

C'(x) = 400 − 5.2x + 0.012x².

Also, revenue, R(x) = x × P(x)

Revenue, R(x) = x(1600 − 8x)

Revenue, R(x) = 1600x − 8x²

Next, we would differentiate the revenue function to derive the marginal revenue:

R'(x) = 1600 - 8x

At maximum profit, the marginal revenue is equal to the marginal cost:

1600 - 8x = 400 − 5.2x + 0.012x

1600 - 8x - 400 + 5.2x - 0.012x² = 0

1200 - 2.8x - 0.012x² = 0

0.012x² + 2.8x - 1200 = 0

Solving by using the quadratic equation, we have:

x = 220.40 or x = -453.73.

Since profit can't be negative, the production level that'll maximize profit is approximately equal to 220.

Read more on maximized profit here: brainly.com/question/13800671

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6 0
2 years ago
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Answer:

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8 0
3 years ago
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Step-by-step explanation:

In pic

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2 years ago
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4 0
3 years ago
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Answer:

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