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rusak2 [61]
3 years ago
15

Recommendations

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
4 0

Answer:

4

Step-by-step explanation:

you're just going to plug in 15 where f is so its asking 15-11 which would be four

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Write the equation of a line that contains (2,−2) and perpendicular to another line with slope −1. (20 POINTS)
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Y=mx+b or -2=-1 x 2+b, b= -2(-1)(2) b=0

Therefore the equation of the line is

y=-1x
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pav-90 [236]
Cross Multiply by 'x - 5'
Hence
y(x - 5) = 4 -3x
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Move all the terms containing an 'x' to one side of the equals and all the others to the opposite side.
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8 0
3 years ago
Consider the following system of equations: 10 + y = 5x + x2 5x + y = 1 The first equation is an equation of a . The second equa
aleksley [76]

Answer: The first equation is an equation of a parabola. The second equation is an equation of a line.

Explanation:

The first equation is,

10+y=5x+x^2

In this equation the degree of y is 1 and the degree of x is 2. The degree of both variables are not same. Since the coefficients of y and higher degree of x is positive, therefore it is a graph of an upward parabola.

The second equation is,

5x+y=1

In this equation the degree of x is 1 and the degree of y is 1. The degree of both variables are same. Since both variables have same degree which is 1, therefore it is linear equation and it forms a line.

Therefore, the first equation is an equation of a parabola. The second equation is an equation of a line.

5 0
3 years ago
Read 2 more answers
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