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Ket [755]
3 years ago
9

A survey of middle school students asked if they play video games. The responses are

Mathematics
1 answer:
kow [346]3 years ago
6 0

Answer:

A. 35.69%

B. 62.77%

Step-by-step explanation:

In this case, what we must do is calculate the probability supported with the data in the table.

Part A.

What is the probability that a randomly selected student is a 7th grader?

Here the total is all the students that would be the sum of all the grades, which are 325 students.

the number of 7th graders is 116, so the probability is:

116/325 = 0.3569

that is, 35.69%

Part B: What percentage of the students interviewed play Video games?

The total number of students is the same 325 and of those 204 play video games, therefore:

204/325 = 0.6277

that is, 62.77%

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Answer:

7

Step-by-step explanation:

You divided both 28 and 4 and you will get 7 as your answer.

7 0
3 years ago
A distribution of values is normal with a mean of 220 and a standard deviation of 13. From this distribution, you are drawing sa
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Answer:

The interval containing the middle-most 48% of sample means is between 218.59 to 221.41.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributied random variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 220, \sigma = 13, n = 35, s = \frac{13}{\sqrt{35}} = 2.1974

Find the interval containing the middle-most 48% of sample means:

50 - 48/2 = 26th percentile to 50 + 48/2 = 74th percentile. So

74th percentile

value of X when Z has a pvalue of 0.74. So X when Z = 0.643.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

0.643 = \frac{X - 220}{2.1974}

X - 220 = 0.643*2.1974

X = 221.41

26th percentile

Value of X when Z has a pvalue of 0.26. So X when Z = -0.643

Z = \frac{X - \mu}{s}

-0.643 = \frac{X - 220}{2.1974}

X - 220 = -0.643*2.1974

X = 218.59

The interval containing the middle-most 48% of sample means is between 218.59 to 221.41.

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Komok [63]

Answer:

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Step-by-step explanation:

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Answer:

Use an online converter but there is something you should know

Step-by-step explanation:

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