The answer in slope-intercept form would be:
y=1/3x-3
The easiest way would be to graph both of them on a coordinate plane. You can either use one online or on your own. When you do graph them, it shows the two lines ARE parallel. I hoped i could help you. Plz mark as brainlies im almost at 5 brainliest so plz mark as brainliest. Thank you very much!
<span>a) In which quadrant of the coordinate plane is point A located? Quadrant I
b) what are the coordinates of translated point A'? in which quadrant of the coordinate plane is point A located? (5,-3) ; Quadrant IV
c) what are the coordinates of reflected point A''? in in which quadrant of the coordinate plane is point A located? (-5,-3) ; Quadrant III
Pls. see attachment. </span>
Answer:
x - 16.1°C
Step-by-step explanation:
Given that average low temperature in January is 16.1 cooler Than average low temperature in November
Let average low temperature in November = x
Since, average low temperature in January is cooler than average low temperature in November, then, January temperature is less Than in November
Hence,
Average low temperature in January :
[Average low temperature in November - 16.1°C]
(x - 16.1°C)