(4/9) divided by (2/3) is 2/3 because you do the reciprocal and mul. Then you mult it by the reciprocal of (5/6) which is (6/5) and get 4/5
2.5 still if you make it a fraction it would be 2 and 1 1/2 so you can't simplify that any more
If you do in fact mean
(as opposed to one of these being the derivative of
at some point), then integrating twice gives



From the initial conditions, we find


Eliminating
, we get


![C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)](https://tex.z-dn.net/?f=C_1%20%3D%20-%5Cdfrac%7B%5Cln%286%29%7D5%20%3D%20-%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%20%5Cimplies%20C_2%20%3D%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29)
Then
![\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}](https://tex.z-dn.net/?f=%5Cboxed%7Bf%28x%29%20%3D%20%5Cln%7Cx%7C%20-%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%5C%2Cx%20%2B%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%7D)
Do it step by step
ab+3c
(-6)(-2)+3(5)
A negative times a negative is positive. (-)(-)=+
12+3(5)
12+15
=27
Answer:
x = 400 when y = 100
Step-by-step explanation:
This is a question in relation to direct variation.
y ∝ 
y = k 
Given that, y = 45, x = 81. Then;
45 = k 
45 = 9k
k = 
k = 5
Thus the relationship among the variables is;
y = 5 
If y = 100, then;
100 = 5 
= 
= 20
x = 
x = 400
Therefore, x = 400 when y = 100.