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VladimirAG [237]
3 years ago
6

Otto is told the average low temperature in January is 16.1∘C cooler than the average low temperature in November. What equation

can Otto use to find the average low temperature in January?
Mathematics
1 answer:
posledela3 years ago
7 0

Answer:

x - 16.1°C

Step-by-step explanation:

Given that average low temperature in January is 16.1 cooler Than average low temperature in November

Let average low temperature in November = x

Since, average low temperature in January is cooler than average low temperature in November, then, January temperature is less Than in November

Hence,

Average low temperature in January :

[Average low temperature in November - 16.1°C]

(x - 16.1°C)

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65+30x

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Use the following scenario to answer the question below:
Stolb23 [73]

The bigger engine is about 235.5 cubic centimeters larger than the smaller engine.

We need the answer in cubic centimeters. So let's convert 350 cubic inches to cubic centimeters. We will do it unit conversion way (the long way).

We will write cubic inches as three inches side-by-side

350 in^3

<h3>What is the ratio of the centimeter?</h3>

This way, we can multiply this by the ratio of centimeters to inches [2.54 cm = 1 inch], so that the units cancel and we have cubic centimeters (what we desire).

350 in^3*3.54cm/1in*3.54cm/1in*3.54cm/1in

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350 in^3*3.54cm/1in*3.54cm/1in*3.54cm/1in.

350 in^3*3.54cm/1in*3.54cm/1in*3.54cm/1in=5735.47.

So 350 cubic inches is approximately 5735.5 cubic centimeters (rounded to 1 decimal place).

This is larger than a 5500 cubic centimeters engine.

5735.5-5500=235.5cubic centimeters.

The bigger engine is about 235.5 cubic centimeters larger than the smaller engine.

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Determine whether the triangles are congruent by AA., SSS, SAS, or not similar.
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A group of 11 people are going to the movies one Saturday. Adult tickets cost $12.50 each and child tickets cost $7.75 each. If
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