The length of QS ANDtv is 8 if not that what are the question answers
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Step 1: Find f'(x):
f'(x) = -6x^2 + 6x
Step 2: Evaluate f'(2) to find the slope of the tangent line at x=2:
f'(2) = -6(2)^2 + 6(2) = -24 + 12 = -12
Step 3: Find f(2), so you have a point on y=f(x):
f(2) = -2·(2)^3 + 3·(2)^2 = -16 + 12 = -4
So, you have the point (2,-4) and the slope of -12.
Step 4: Find the equation of your tangent line:
Using point-slope form you'd have: y + 4 = -12 (x - 2)
That is the equation of the tangent line.
If your teacher is picky and wants slope-intercept, solve that for y to get:
y = -12 x + 20
Hello , can you please give me a thanks bc I need help myself and I’m failing math and I need to “answer “ 2 questions for me to ask mine
Answer: Given as,X=2 & Y=3,
now multiplying we get,
2xxy=2×2×3=12
Ans.) 12
Step-by-step explanation: