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marysya [2.9K]
3 years ago
8

an object is acted upon by a force of 22 Newtons to the right and 13 Newtons to the left what is the magnitude and direction of

the net force ​
Physics
1 answer:
frosja888 [35]3 years ago
8 0

22N to the right and 13N to the left

Forces are in opposite directions so you subtract the bigger force from the smaller force

Magnitude of force= 22N -13N

= 9N

net force direction is to the right

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Water of density 1000 kg/m3 falls without splashing at a rate of 0.373 L/s from a height of 40.5 m into a 0.64 kg bucket on a sc
Sphinxa [80]

Answer:

       F_scale = 20.18 N

Explanation:

The scale reading corresponds to two factors, the first the weight of the water in the container and the second the force of the liquid that is falling at the moment of reading.

* Let's find the amount of liquid in the container for a time of t = 2.93 s

Let's use a direct proportion rule. If 0.373 l falls in one second at t = 2.93 s, how many liters are there

        V_{water} = 2.93 s (0.373 l / 1s) = 1.09 l

        V_{water} = 1.09 10⁻³ m³

the amount of water is

       ρ = m / V

       m = ρ V

       m = 1000 1.09 10⁻³

       m = 1.09 kg

so the weight of the liquid in the container for this time is

       W = mg

       W = 1.09 9.8

       W = 10.68 N

* Let's look for the force of the falling jet

Let's use Bernoulli's equation, where the subscript 1 is for the container and the subscript 2 is for the water at a height h

        P₁ + 1/2 ρ g v₁² + ρ g y₁ = P₂ + 1/2  ρ g v₂² + ρ g y₂

In this case, the water falls freely, so the external pressure is atmospheric.

         P₂ = P_{atm}

since they indicate that the water falls, we assume that its initial velocity is zero v₂ = 0

let's use kinematics to find the speed of a drop when it reaches the container y = 0

         v² = v₀² - 2 g (y-y₀)

         v = \sqrt{0 -2 g ( 0-y_o)}

let's calculate

         v = √(2 9.8 40.5)

         v = 28.17 m / s

this is the speed in the container v₁ = 28.17 m / s

the height from where it falls is y₂ = 40.5 and reaches the container y₁ = 0

we substitute in Bernoulli's equation

         P₁ +1/2 ρ g v₁² + 0 = P_{atm} + 0 + ρ g y₂

         P₁ + ½ ρ g v₁² = P_{atm} + ρ g y₂

         P₁ = P_{atm} + ρ g y₂ - ½ ρ g v₁²

         P₁ = 1 10⁵ + 1000 9.8 40.5 - ½ 1000 28.17²

         P₁ = 1 10⁵ + 3.97 10⁵ - 3.69 10⁵

         P₁ = 1.28 10⁵ Pa

The definition of Pressure is

         P = F / A

         F = P A

We must suppose a time to carry out the reading suppose an average time of the modern equipment t = 0.1 s, in this time how much is now arriving

          m₂ = 0.373 0.2 = 0.0746 l = 0.0746 10⁻³ m³

the volume is V = A l

if the length of l = 1 m

A = 0.0746 10⁻³ m³ = 7.45 10⁻⁵ m²

the force of this jet is

            F = P A

            F = 1.28 10⁵  7.46 10⁻⁵

            F = 9.5 N

with these data let's use the equilibrium equation

           F_ scale -W - F = 0

           F_scale = W + F

           F_scale = 10.682 + 9.5

           F_scale = 20.18 N

4 0
3 years ago
Which scientific law describes the relationship between action and reaction force pairs? Newton's third law of motion Kepler's l
Hitman42 [59]

Newton's third law of motion

Explanation:

Newton's third law of motion states that:

<em>"When an object A exerts a force on an object B (action force), then object B exerts an equal and opposite force (reaction force) on object A"</em>

It is important to note that this law is always valid, even when it seems it is not.

Consider for example the gravitational force that the Earth exerts on your body (= your weight). We can say that this is the action force. It may seems that there is no reaction force in this case. However, this is not true: in fact, your body also exerts an equal and opposite force on the Earth, and this is the reaction force. The reason that explains why we don't notice any effect on Earth due to this force is that the mass of the Earth is much larger than your mass, therefore the acceleration produced on the Earth because of the force you apply is negligible.

It is also important to note that the action-reaction pair of forces always act on two different objects, so they never appear in the same free-body diagram.

Learn more about Newton's third law of motion:

brainly.com/question/11411375

#LearnwithBrainly

7 0
4 years ago
Unpolarized light is passed through three successive Polaroid filters, each with its transmission axis at 45.0° to the preceding
allsm [11]

Answer:

The percentage is  k = 12.5 \%

Explanation:

From the question we are told that

    The  axis is is  at  \theta =  45 ^o

Generally the of intensity light emerging from the first polarizer is mathematically represented as

                I_{1} =  \frac{I_o}{ 2}

Where  I_o is the intensity of unpolarized light

       Now the light emerging from the second polarizer is mathematically represented as

         I_2  = I_ 1 * cos ^2(\theta )

         I_2  = \frac{I_o}{2}  * cos ^2(45 )

        I_2  = \frac{I_o}{2} *  \frac{1}{2}  =  \frac{I_o}{4}

  Now the light emerging from the third  polarizer is mathematically represented as      

       I_3  = I_ 2 * cos ^2(\theta )

       I_3  = \frac{I_o}{4}   * cos ^2(45 )

      I_3  = \frac{I_o}{8}

Now the percentage of the intensity of light that emerged with respect to the intensity of  the unpolarized light is

      k =  \frac{\frac{I_o}{8} }{I_o }  * 100

     k = 12.5 \%

       

3 0
3 years ago
What equipment is essential for filtering a solid from a liquid?
fredd [130]
B) <span>Beaker, funnel, filter paper, stirring rod, iron ring, and stand</span>
4 0
4 years ago
Uranus and neptune have methane clouds but jupiter and saturn do not. Which factor explains why?.
mr Goodwill [35]

Answer:

Temperature on Jupiter and Saturn are too high for methane to condense.

Explanation:

However, methane can condense on Uranus and Neptune because they are farther from the sun and hence colder.

4 0
2 years ago
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