Length x width = area
<span>but
1feet=12</span><span>inches
</span>8 x 12=96
10<span>x96=960</span>
(8x + 2y) - (7x + 2y) = 30 - 24
X = 6
First remove the parenthes as there is a negtive outside the second parentheses the signs of the terms inside change.
= 2n^4 - 8 - 3n - 4n^2 - 7n - 4
Now simplify like terms
= 2n^4 - 4n^2 - 10n - 12
= 2(n^4 - 2n^2 - 5n - 6)
The distance, s = 40t₁ where t₁ is the time to complete the outward journey.
The same distance = vt₂ where t₂ is the time to complete the return journey at speed v.
For the whole journey, 2s=60(t₁+t₂). Therefore s=30(t₁+t₂)=40t₁=vt₂.
30t₁+30t₂=40t₁, 10t₁=30t₂, t₁=3t₂, so s=120t₂=vt₂ and v=120kph.
Answer:
z= 2.38
P = 0.008656
Step-by-step explanation:
Here n= 500 and p~= 464/500= 0.928 and q`= 1- 0.928 = 0.072
We formulate our null and alternate hypothesis as
H0 = 0.9 ; H0 > 0.9
The degree of confidence = 90%
z₀.₀₅ = 1.645 for α= 0.05
We use the test statistic
z= x- np/√npq
z= 466-500 *0.9/ √500 * 0.9(1-0.9)
z= 466- 450/ √45
z= 16/6.7082
z= 2.38
As the calculated value of z= 2.38 is greater than α =1.645 so we reject H0.
If H0 is true the P value is calculated as
P = 1- Ф( 2.38)
P = 1-0.991344=0.008656
