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Elena L [17]
3 years ago
6

A packet of sweets contains only blue and red sweets the ratio of blue to red sweets in a packet is 2:1 if there are 12 sweets i

n total how many red sweets are there
Mathematics
2 answers:
storchak [24]3 years ago
8 0
4.
Ratio of blue = 1
Total ratio = 3

1/3 x 12 = 4
Anna007 [38]3 years ago
6 0

Answer:

4 red swets

Step-by-step explanation:

2 + 1 = 3 (Total units of both red and blue sweets)

3 units = 12

1 unit = 12 ÷ 3 = 4

Since red sweets has only 1 unit, there are 4 red sweets out of 12 sweets.

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Line segment GH is divided by point J in the ratio of 1:4. Endpoint G is at (7,5) and point J is at (10, 14).
wlad13 [49]

Answer:

(x2 , y2) = (22,50)

Step-by-step explanation:

Given:

m1 : m2 = 1:4

(x1 , y1) = (7 , 5)

(X ,Y) = (10 ,14)

Find:

(x2 , y2)

Computation:

X = (m1x2 + m2x1) / (m1+m2)

10 = [(1)(x2) + (4)(7)]/(1+4)

10 = [x2 + 28]/5

22 = x2

Y = (m1y2 + m2y1) / (m1+m2)

14 = [(1)(y2) + (4)(5)]/(1+4)

14 = [y2 + 20]/5

70 = y2 + 20

50 = y2

(x2 , y2) = (22,50)

7 0
3 years ago
What is the measure of angle G?<br><br>Please help I’m so confused
Nana76 [90]

Answer:

angle G is 45 degrees

Step-by-step explanation:

all sides of a triangle add up to 180 degrees. looking at the triangle, the angles that we are provided are E and F. E is 90 degrees, and F is 45 degrees. If you add those together, we get 135. then, subtract 180 from 135, and you get your answer, which is 45 degrees.

also, it says on the smaller triangle in the bottom left.

hope this was helpful :D

3 0
2 years ago
Read 2 more answers
The product of a number and 4 increased by 16 is -2
NikAS [45]

Let n = the unknown number

"The product of a number and 4" = 4 * n = 4n

"increased by 16" = + 16

Set it all equal to - 2.

4n + 16 = - 2

Subtract 16 from both sides to get constants on one side and variables on the other.

4n = - 2 - 16

Combine like terms:

4n = - 18

Divide both sides by 4 to isolate variable n.

n = - 18 / 4

= - 4 and 2/4 = - 4 and 1/2

3 0
3 years ago
If f(x) = sin(x/2), then there exists a number c in the interval pie/2 &lt; x &lt; 3pie/2 that satisfies the conclusion of the m
elena-14-01-66 [18.8K]
For the answer to the question above, 
The mean value theorem states the if f is a continuous function on an interval [a,b], then there is a c in [a,b] such that: 
<span>f ' (c) = [f(b) - f(a)] / (b - a) </span>
<span>
So [f(a) - f(b)] ( b - a ) = [sin(3pi/4) - sin(pi/4)]/pi </span>
= [sqrt(2)/2 - sqrt(2)/2]/pi = 0 
So for some c in [pi/2, 3pi/2] we must have f ' (c) = 0 

In general f ' (x) = (1/2) cos (x/2) 
We ask ourselves for what values x in [pi/2, 3pi/2] does the above equation equal 0. 
0 = (1/2) cos (x/2) 
0 = cos (x/2) 
x/2 = ..., -5pi/2, -3pi/2, -pi/2, pi/2, 3pi/2, 5pi/2,... 
x = ..., -5pi, -3pi, -pi, pi. 3pi, 5pi, .... 
and x = pi is the only solution in our interval. 

So c = pi is a solution that satisfies the conclusion of the MVT
3 0
3 years ago
Don waled 3 3/5 miles on friday, 3.7 miles on saturday and 3 5/8 miles on sunday. List the distances from least to greatest.
marta [7]
The answer is 3 3/5, 3 5/8, 3.7
3.6. 3.625. 3.7
6 0
3 years ago
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