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jenyasd209 [6]
3 years ago
5

N/5 - 3n/10 = 1/5 check it please

Mathematics
1 answer:
Art [367]3 years ago
4 0

Answer:

n=-2

Step-by-step explanation:

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Please help explanation if possible
Nookie1986 [14]

Answer:

y=-3x+5

Step-by-step explanation:

concepts: y=mx+b is slope intercept equation formula

m=slope

b= y intercept

Therefore we need to find the slope and y intercept

first find slope

m=\frac{y2-y1}{x2-x1}

let y2 be 2

let y1 be -4

let x2 be 1

let x1 be 3

\frac{2-(--4)}{1-3}

6/-2 = -3

m=-3

slope is -3

y= -3x+ b

we need find y intercept now

just plug in (1,2) into that equation

2=-3(1)+b

b=5

y=-3x+5

5 0
3 years ago
What algebraic expression is a product with a factor of 5
USPshnik [31]

Answer:

y=5x

Step-by-step explanation:

A product means multiplication, and you need to multiply x by 5 in order to make the product have a factor of 5.

4 0
2 years ago
Correct answer gets brainliest!!<br><br> Does someone know the answers to these question
VARVARA [1.3K]

Use Ga_thMath(u) (brainly doesn't allow me to type it) To use the app u need to take a pic of the problem and then it will process it and you'll get ur answer ASAP(most of the time). Many questions have been asked before so search it on brainly.

4 0
3 years ago
There are 20 girls and 26 boys on the tennis team.
salantis [7]

Answer:

B 1013

Step-by-step explanation:

because 20/2 is 10 and 26/2 is 13 so 1013

6 0
3 years ago
Read 2 more answers
Sherman has two sequences . The first sequence is described by the explicit rule f(n) = 15n + 4 and the second sequence is descr
Viktor [21]

Answer:

Step-by-step explanation:

Given the explicit function as

f(n) = 15n+4

The first term of the sequence is at when n= 1

f(1) = 15(1)+4

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 15(2)+4

f(2) = 34

d = 34-19

d = 15

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)15)

S20 = 10(38+19(15))

S20 = 10(38+285)

S20 = 10(323)

S20 = 3230.

Sum of the 20th term is 3230

For the explicit function

f(n) = 4n+15

f(1) = 4(1)+15

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 4(2)+15

f(2) = 23

d = 23-19

d = 4

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)4)

S20 = 10(38+19(4))

S20 = 10(38+76)

S20 = 10(114)

S20 = 1140

Sum of the 20th terms is 1140

7 0
3 years ago
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