Question

Which ordered pair (m, n) is a solution to the given system of linear equations? mc015-1.jp g (–4, –1) mc015-2.jp g (–1, –4) (11, –16)

Answer 1

Answer:

(-1,-4)

Step-by-step explanation:

6m-5n=14  equation 1

2m+2n= -10  equation 2

using equation 2 we have

2m=-10-2n

m=-5-n equation 3

using equation 1  we have

6*(-5-n)-5n=14

-30-6n-5n=14

-11n=14+30

-11n=44

n=-44/11

n=-4

using equation 3

m=-5-n

m=-5-(-4)

m=-1

finally we have

(-1,-4)

Answer 2

Answer:

The ordered pair (m, n) which is a solution to the given system of linear equations is:

                                  (-1,-4)

Step-by-step explanation:

We are given a system of linear equations as follows:

             $6m-5n=14-------(1)$

and

             $2m+2n=-10$

which could be reduced as follows:

 $m+n=-5--------(2)$

( Since, we divide both side by 2)

Now, on multiplying equation (2) by 5 and adding both the equations we get:

$11m=-11\\\\m=\dfrac{-11}{11}\\\\m=-1$

On putting the value of m in  equation (2) we get:

$-1+n=-5\\\\n=-5+1\\\\n=-4$

Hence, the ordered pair which is a solution is given by:

                                 (-1,-4)