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3 years ago

A right triangle is shown below. Which measurement is the closest to the value of x?

Mathematics

1 answer:

REY [17]3 years ago

6 0

Answer:

35°

Step-by-step explanation:

First you find the sine of x. That would be

sinx = opposite/hypotenuse

sinx = 57/100

sinx = 0.57

You can look it up if you want, but sin35 = 0.574

so the answer is 35°

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Use mathematical induction to show that 4^n ≡ 3n+1 (mod 9) for all n equal to or greater than 0

cestrela7 [59]

When $n=0$ , you have

$4^0=1\equiv3(0)+1=1\mod9$

Now assume this is true for $n=k$ , i.e.

$4^k\equiv3k+1\mod9$

and under this hypothesis show that it's also true for $n=k+1$ . You have

$4^k\equiv3k+1\mod9$
$4\equiv4\mod9$
$\implies 4\times4^k\equiv4(3k+1)\mod9$
$\implies 4^{k+1}\equiv12k+4\mod9$

In other words, there exists $M$ such that

$4^{k+1}=9M+12k+4$

Rewriting, you have

$4^{k+1}=9M+9k+3k+4$
$4^{k+1}=9(M+k)+3k+3+1$
$4^{k+1}=9(M+k)+3(k+1)+1$

and this is equivalent to $3(k+1)+1$ modulo 9, as desired.

3 0

3 years ago

Write an expression that can be used in over a temperature from degrees Celsius see to degrees Fahrenheit and then use the expre

densk [106]

Answer:

25°C = 77 degree Fahrenheit.

Step-by-step explanation:

In this question we have to write the expression showing the relation between degree Celsius and degree Fahrenheit first.

$C=\frac{5}{9}(F-32)$ where C = degree centigrade and F = degree Fahrenheit

Although the question is not clear in the next part but assuming that we have to use this expression to convert 25°C to degree Fahrenheit,

We will plug in the value of C in the expression,

$25=\frac{5}{9}(F-32)$

$F=(\frac{9}{5}\times 25)+32$

F = 45 + 32

F = 77

Therefore, 25°C = 77 degree Fahrenheit will be the answer.

4 0

3 years ago

When you have 25 numbers, and Jake picks 3 random numbers and puts them back, what is the chance Bob has of picking those 3 numb

tensa zangetsu [6.8K]

Answer:

4 out of 25 percent chance

Step-by-step explanation:

if you divide the number and range them out. That's all i can tell you for now. Kinda busy. sorry

7 0

3 years ago

Can someone please help me with this

Sholpan [36]

Answer:

39 sq inches

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the nth term rule of the quadratic sequence below? 4,15,30,49,72,99,130,...

navik [9.2K]

Answer:

The nth term rule of the quadratic sequence is $2n^{2} +5n-3$ .

Step-by-step explanation:

We are given the following quadratic sequence below;

4, 15, 30, 49, 72, 99, 130,...

As we know that the formula for the nth term of the quadratic sequence is given by = $an^{2}+bn+c$

Firstly, we will find the difference between the term of the given sequence;

1st difference of the given sequence;

(2nd term - 1st term), (3rd term - 2nd term), (4th term - 3rd term), (5th term - 4th term), (6th term - 5th term), (7th term - 6th term)

= (15 - 4), (30 - 15), (49 - 30), (72 - 49), (99 - 72), (130 - 99),....

= (11, 15, 19, 23, 27, 31,.....)

Now, we will find the second difference of the given sequence, i.e;

= (15 - 11), (19 - 15), (23 - 19), (27 - 23), (31 - 27),....

= (4, 4, 4, 4, 4)

Since the differences are same now, so to find the value of a we have to divide the value of second difference by 2, i.e;

The value of a = $\dfrac{4}{2}$ = 2

SO, the first term of the nth term rule equation is $an^{2}$ = $2n^{2}$ .

Now, in the term $2n^{2}$ , put the value of n = 1, 2, 3, 4 and 5 and then form the sequence, i.e;

If n = 1, then $2n^{2}$ = $2 \times (1)^{2}$ = 2

If n = 2, then $2n^{2}$ = $2 \times (2)^{2}$ = 8

If n = 3, then $2n^{2}$ = $2 \times (3)^{2}$ = 18

If n = 4, then $2n^{2}$ = $2 \times (4)^{2}$ = 32

If n = 5, then $2n^{2}$ = $2 \times (5)^{2}$ = 50

SO, the sequence formed is (2, 8, 18, 32, 50).

Now, find the difference of this sequence and the original quadratic sequence, i.e;

= (4 - 2), (15 - 8), (30 - 18), (49 - 32), (72 - 50)

= (2, 7, 12, 17, 22)

Now, as we can see that the above sequence resembles the general form of (5n - 3) because:

If we put n = 1, then (5n - 3) = 5 - 3 = 2

If we put n = 2, then (5n - 3) = 10 - 3 = 7 and so on....

From this, we concluded that the value of b and c are 5 and (-3) respectively.

Hence, the nth term rule for the given quadratic sequence is $2n^{2} +5n-3$ .

7 0

3 years ago