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g100num [7]
3 years ago
15

Ari thinks the perfect milkshake has 333 ounces of caramel for every 555 scoops of ice cream. Freeze Zone makes batches of milks

hakes with 666 ounces of caramel and 888 scoops of ice cream.
What will Ari think about Freeze Zone's milkshakes?
Mathematics
1 answer:
Maksim231197 [3]3 years ago
8 0

Answer:

Ari will think that Feeze Zone makes milkshakes with too much caramel.

Step-by-step explanation:

First off I took 3 ounces of caramel to 5 scoops of ice cream, which makes a ratio of 3/5.

Freeze Zone makes milkshakes with 6 ounces of caramel, so I multiplied the 3 and the 5 by two to get 6 ounces of caramel for the ratio.

once you multiply the ratio by two it becomes 6/10 and the milkshakes that Freeze Zone makes are 6/8, so they have more caramel than Ari likes.

Sorry if the explanation is a little confusing, I hope it helped :)

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Solve the system x+3=22 2x-y=2
steposvetlana [31]

Hello from MrBillDoesMath!

Answer:

x = 19, y = 36

Discussion:

x + 3 = 22     (*)

2x - y = 2      (**)


Subtract 3 from both sides of (*)

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x = 19


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38 - y = 2 =>           (add y to both sides)

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3 0
3 years ago
From the sum of 2 and -11, subtract the sum of 2 and -6<br>​
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7 0
3 years ago
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Box of 15 gadgets is known to contain 5 defective gadgets if 4 gadgets are drawn at random what is the probability of finding no
baherus [9]

To solve this problem, we make use of the Binomial Probability equation which is mathematically expressed as:

P = [n! / r! (n – r)!] p^r * q^(n – r)

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r = number of samples = 1 and 2 (since not more than 2)

p = probability of success of getting a defective gadget

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Calculating for p:

p = 5 / 15 = 0.33

So,

q = 1 – 0.33 = 0.67

 

Calculating for P when r = 1:

P (r = 1) = [4! / 1! 3!] 0.33^1 * 0.67^3

P (r = 1) = 0.3970

 

 

Calculating for P when r = 2:

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P (r = 2) = 0.2933

 

Therefore the total probability of not getting more than 2 defective gadgets is:

P = 0.3970 + 0.2933

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Hence there is a 0.6903 chance or 69.03% probability of not getting more than 2 defective gadgets.

5 0
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