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My name is Ann [436]
3 years ago
7

I NEED THIS ANSWER AAAAA

Mathematics
1 answer:
enyata [817]3 years ago
5 0
The answer is 400 because 40.00*8.5 is 340.00. Add on the 60 dollar service charge and get 400.00.

Hope this helped :)
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What is the measure of angle f?
dlinn [17]

Answer:

130 fj is a little bit of a good job for the first time in a new generation of companies in a little

Step-by-step explanation:

its 130 inches tall and a good job to do with my first day of work at a time when the first thing you can get to the point where

3 0
3 years ago
A=1/4 and b=6.<br><br> −8ab=
podryga [215]

Answer:

When a=\frac{1}{4} and b=6:

-8ab=-12

Step-by-step explanation:

-8ab can be seen as -8×a×b. Insert the given values:

-8*\frac{1}{4} *6

Simplify multiplication from left to right:

-8*\frac{1}{4} \\\\\frac{-8}{1} *\frac{1}{4} =\frac{-8}{4} =-2

Insert and solve:

-2*6=-12

:Done

3 0
3 years ago
The table gives the probability distribution of the annual rate of return on the stock of MNP Company, Inc. What is the expected
krok68 [10]
For the answer to the question above,
The expected value in percentage format is 0.2 x 15+0.4 x 20 + 0.3 x 30 + 0.1*35 = <u><em>23.5%</em></u>
The answer is <u><em>23.5%
</em></u>

I hope my answer helped you. Have a nice day ahead!
<u><em /></u>
8 0
3 years ago
Read 2 more answers
Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)
Dima020 [189]

Split C into two component segments, C_1 and C_2, parameterized by

\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)

\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)

respectively, with 0\le t\le1, where \mathbf r_i(t)=(x(t),y(t)).

We have

\mathrm d\mathbf r_1=(6,1)\,\mathrm dt

\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt

where \mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt

so the line integral becomes

\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)

=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt

=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6

6 0
3 years ago
One third of a number Y
vampirchik [111]

Answer:

⅓y

Step-by-step explanation:

\frac{1}{3}  \times y \\  =  \frac{1}{3} y

4 0
3 years ago
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