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2 years ago

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Mathematics

1 answer:

agasfer [191]2 years ago

7 0

the is just THIS ONE JIAN JUAN IS B

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PLS HELP!! :))<br><br> Find the volume......

OLEGan [10]

Answer:

19 + 14 + 10 = 43

Step-by-step explanation:

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2 years ago

G find the area of the surface over the given region. use a computer algebra system to verify your results. the sphere r(u,v) =

Svetach [21]

Presumably you should be doing this using calculus methods, namely computing the surface integral along $\mathbf r(u,v)$ .

But since $\mathbf r(u,v)$ describes a sphere, we can simply recall that the surface area of a sphere of radius $a$ is $4\pi a^2$ .

In calculus terms, we would first find an expression for the surface element, which is given by

$\displaystyle\iint_S\mathrm dS=\iint_S\left\|\frac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

$\dfrac{\partial\mathbf r}{\partial u}=a\cos u\cos v\,\mathbf i+a\cos u\sin v\,\mathbf j-a\sin u\,\mathbf k$
$\dfrac{\partial\mathbf r}{\partial v}=-a\sin u\sin v\,\mathbf i+a\sin u\cos v\,\mathbf j$
$\implies\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}=a^2\sin^2u\cos v\,\mathbf i+a^2\sin^2u\sin v\,\mathbf j+a^2\sin u\cos u\,\mathbf k$
$\implies\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|=a^2\sin u$

So the area of the surface is

$\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=\pi}\int_{v=0}^{v=2\pi}a^2\sin u\,\mathrm dv\,\mathrm du=2\pi a^2\int_{u=0}^{u=\pi}\sin u$
$=-2\pi a^2(\cos\pi-\cos 0)$
$=-2\pi a^2(-1-1)$
$=4\pi a^2$

as expected.

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2 years ago

A computer that originally cost $850 is on sale for

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Answer: 722.5 this is after sale

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2 years ago

Graph y = x2 – 2x – 3. (Identify the y-intercept.)

Pavlova-9 [17]

Answer:

Your y-intercept is (0,-3)

Step-by-step explanation:

I rec. using desmos graphing calculator it makes questions like that 10x easier.

Hope this helps! :)

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3 years ago

The results are shown in the circle graph. Find arc mAB

Ainat [17]

If you show me a picture of the problem I could help you, but I can’t see the circle sooo I can’t help u unless I see it

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3 years ago