The sum of first 20 arithmetic series 
Given:
Arithmetic series for 3rd term is 55
Arithmetic series for 7th term is -98
To find:
The sum of first 20 Arithmetic series
<u>Step by Step Explanation:
</u>
Solution:
Formula for calculating arithmetic series
Arithmetic series=a+(n-1) d
Arithmetic series for 3rd term 
Arithmetic series for 19th term is
Subtracting equation 2 from 1
![\left[a_{19}+18 d=-98\right]+\left[a_{1}+2 d=55\right]](https://tex.z-dn.net/?f=%5Cleft%5Ba_%7B19%7D%2B18%20d%3D-98%5Cright%5D%2B%5Cleft%5Ba_%7B1%7D%2B2%20d%3D55%5Cright%5D)
16d=-98-55
16d=-153
Also we know
First 20 terms of an AP
![a_{20}=[1106 / 16]-[2907 / 16]](https://tex.z-dn.net/?f=a_%7B20%7D%3D%5B1106%20%2F%2016%5D-%5B2907%20%2F%2016%5D)
Sum of 20 Arithmetic series is
Substitute the known values in the above equation we get
![S_{20}=\left[\frac{20\left(\left(\frac{558}{8}\right)+\left(\frac{-1801}{16}\right)\right)}{2}\right]](https://tex.z-dn.net/?f=S_%7B20%7D%3D%5Cleft%5B%5Cfrac%7B20%5Cleft%28%5Cleft%28%5Cfrac%7B558%7D%7B8%7D%5Cright%29%2B%5Cleft%28%5Cfrac%7B-1801%7D%7B16%7D%5Cright%29%5Cright%29%7D%7B2%7D%5Cright%5D)
![S_{20}=\left[\frac{\left.20\left(\frac{1106}{16}\right)+\left(\frac{-1801}{16}\right)\right)}{2}\right]](https://tex.z-dn.net/?f=S_%7B20%7D%3D%5Cleft%5B%5Cfrac%7B%5Cleft.20%5Cleft%28%5Cfrac%7B1106%7D%7B16%7D%5Cright%29%2B%5Cleft%28%5Cfrac%7B-1801%7D%7B16%7D%5Cright%29%5Cright%29%7D%7B2%7D%5Cright%5D)
![S_{20}=5\left[\frac{-695}{16}\right]](https://tex.z-dn.net/?f=S_%7B20%7D%3D5%5Cleft%5B%5Cfrac%7B-695%7D%7B16%7D%5Cright%5D)
Result:
Thus the sum of first 20 terms in an arithmetic series is
Answer:
the answer is c i took the quiz
Step-by-step explanation:
The answer is: J - 3.08 pounds
Answer:
When we have a number like:
1.0x10^n
To rewrite this in standard form, we need to:
if n is positive, we move the decimal point n times to the right, adding zeros when necessary.
1.0x10^3
n = 3. then we add 3 zeros between the one and the decimal point, this is:
1.0x10^3 = 1000
if n< 0, then we move the decimal point n times to the left.
If we had:
1.0x10^-3
We move the decimal point 3 times to the left, adding zeros as this is needed.
1.0x10^-3 = 0.001
if n = 0, we have:
1.0x10^0 = 1.0
Now let's rewrite all the given numbers:
A) 3.4x10^-1 = 0.34
B) 1.36x10^6 = 1360000
C) 7.9x10^0 = 7.9
D) 2.4x10^5 = 240000
E) 5.21x10^-3 = 0.00521
F) 4.3x10^-2 = 0.043
U have to measure what ever your measuring example
say your measuring a square measure the sides like this --> |_| <---
these sides
enjoy
