The mass of chlorine that react with 9.00 g of Al to form AlCl3 is 35.465 grams
Explanation
write the equation for reaction
that is
2 Al + 3 Cl2 = 2 Al CL3
find the moles of Al reacted
moles = mass/molar mass
9 g/ 27 g/mol = 0.333 moles of Al
by use of mole ratio between Al to Cl2 which is 2:3 find the moles of Cl2
mole of cl2 = 0.333 x3/2 = 0.4995 moles
mass of Cl2 is therefore = moles x molar mass
= 0.4995 x71 = 35.465 moles
Answer:
No
Explanation:
The solubility of a solid in water refers to the amount of that solid that dissolves in water.
It is not possible to calculate the solubility of the solid because the student threw away the first precipitate that formed. We already have the volume of water, but having lost some mass of precipitate, it has become impossible to accurately determine the solubility.
Hence the answer provided above.
The amount of the 240 g sample of the radioisotope that will remain after 525 billion years is 7.5 g
<h3>How to the number of half-lives that has elapsed</h3>
- Half-life (t½) = 105 billion years
- Time (t) = 525 billion years
- Number of half-lives (n) = ?
n = t / t½
n = 525 / 105
n = 5
<h3>How to determine the amount remaining</h3>
- Original amount (N₀) = 240 g
- Number of half-lives (n) = 5
- Amount remaining (N) = ?
N = N₀ / 2ⁿ
N = 240 / 2⁵
N = 240 / 32
N = 7.5 g
Learn more about half life:
brainly.com/question/26374513
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Answer:
Continental moderate climet
