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Gemiola [76]
3 years ago
10

Socratic an example of an atom that has no charge is one that has

Chemistry
1 answer:
aksik [14]3 years ago
5 0

An example of an atom that has no charge is one that has a. 2 protons, 2 electrons, and 1 neutron.

To be neutral an atom must have the <em>same number</em> of protons (+) and electrons (-).

Only then will the <em>charges cancel</em> and give a neutral atom.


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Calculate the mole fraction of Ba Cl 2 in an aqueous solution prepared by dissolving 0.400 moles of Ba Cl 2 in 850.0 g of water.
DaniilM [7]

Answer:

0.0084

Explanation:

The mole fraction of BaCl₂ (X) is calculated as follows:

X = moles BaCl₂/total moles of solution

Given:

moles of BaCl₂ = 0.400 moles

mass of water = 850.0 g

We have to convert the mass of water to moles, by using the molecular weight of water (Mw):

Mw of water (H₂O) = (2 x 1 g/mol)+ 16 g/mol = 18 g/mol

moles of water = mass of water/Mw of water = 850.0 g/(18 g/mol) = 47.2 mol

The total moles of the solution is given by the addition of the moles of solute (BaCl₂) and the moles of solvent (water):

total moles of solution = moles of BaCl₂ + moles of water = 0.400 + 47.2 mol = 47.6 mol

Finally, we calculate the mole fraction:

X = 0.400 mol/47.6 mol = 0.0084

4 0
3 years ago
Find the molar mass of vitamin A (C20H30O).
agasfer [191]
Just add up the molar masses of each element.

Molar mass of C:  12.011 g/mol
The equation says C20, which means there are 20 carbon atoms in each molecule of Vitamin A.  So, we multiply 12.011 by 20 to get 240.22 g/mol carbon.

Molar mass of H:  1.0079 g/mol
The equation says C30, which means there are 30 hydrogen atoms in each molecule of Vitamin A. So, we multiply 1.0079 by 30 to get 30.237 g/mol hydrogen.

Molar mass of O: 15.999 g/mol
The equation says O without a number, which means there is only one oxygen atom in each molecule of Vitamin A.  So, we leave O at 15.999 g/mol.

Then, just add it up:
240.22 g/mol C + 30.237 g/mol H + 15.999 g/mol O = 286.456 g/mol C20H30O

So, the molar mass of Vitamin A, C20H30O, is approximately 286.5 g/mol.
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H :) (I tried sorry if im wrong)
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During transcription, RNA polymerase encounters the sequence of DNA
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