Answer:
Rewrite the equation as
3
b
+
4
c
=
a
.
3
b
+
4
c
=
a
Subtract
4
c
from both sides of the equation.
3
b
=
a
−
4
c
Divide each term by
3
and simplify.
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b
=
a
3
−
4
c
3
Step-by-step explanation:
Answer: hypotenuse = 
Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (
) of the right triangle, .i.e.:
In this question:
= 
2bc
Substituing and taking square root to find hypotenuse:
Calculating:
= 
, then:
Hypotenuse for the right-angled triangle is units
Just replace a with 4 and b with 2 and your equation looks like
3.14 (4×2+4×2)
solve within the parenthesis first
3.14 (8+8)
3.14 (16) =50.24
Answer:
see the explanation
Step-by-step explanation:
we know that
The y-intercept is the value of the function y when the value of x is equal to zero
Part 1) we have
For x=0
substitute in the linear equation and solve for y
therefore
The y-intercept is the point (0,-6)
Part 2) Find the y-intercept of the function represented in the graph
Looking at the graph
For x=0
Find the value of y in the graph
The value of y is equal to y=1
therefore
The y-intercept is the point (0,1)
I'm going to separate this into sections so it makes more sense for you to read. For the problems with π where you have to round, ask your teacher where to round, unless your textbook specifies it:
A – 100 cm^2
To calculate area of squares, you multiply l • w. It's a square, so all sides are equal, and since we know that one side = 10 cm, the area is 10 • 10 = 100
B – πr^2 (not sure if the r shows up very well, so I'm retyping it in words - pi • radius squared)
C – 25π cm^2 or an approximate round like 78.54 cm^2 (ask your teacher about this – it could be to the nearest tenth, hundredth, etc.)
To find the area of a circle, you must follow the formula πr^2. In this case, the diameter is 10. The radius is half the diameter, so to substitute the values you must find 10 ÷ 2 = 5. So the radius is 5 cm. From there you can substitute r for 5, ending up with π • 5^2. 5^2 = 25, so the area is 25π, or about 78.54, depending on where the question wants you to round.
D – An approximate round (to the nearest hundredth it is 21.46 cm^2)
To find the area of the shaded region, just subtract the circle's area from the square's area, or 100 – 25π ≈ 21.46. Again, though, ask your teacher about where to round, unless your textbook specifies it.
E – dπ (diameter • pi)
F – 10π cm^2 or an approximate round like 31.42 cm^2
The diameter is 10. 10π ≈ 31.42
Hope this helps!
