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3 years ago

SOMEONE PLSSS HELPP MEE

Mathematics

1 answer:

evablogger [386]3 years ago

8 0

Answer:

Step-by-step explanation:

∛6t^2= (6t^2)^1/3=

also if you want further

6^1/3 t^2/3

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33 is 75% of what number

Alexus [3.1K]

<span>33 / 75=0</span>.44 is the answer

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3 years ago

Which of the following is the correct factorization of the

Helga [31]

Answer:

The answer is b

Step-by-step explanation:

(4x+5)(16^2-20x+25)

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3 years ago

Turn 18% into a fraction

Maslowich

18/100
6/50
3/25

here is a couple different options. the last one being the most simplified. hope this helps

7 0

3 years ago

Read 2 more answers

HELP ME PLS!<br> i need the first 4 examples

BARSIC [14]

Answer:

1) 6а-9b=3(2a-3b)

2)8a-12b=4(2a-3b)

3) 5ab-5ac=5a(b-c)

4) 6ax+6ay=6a(x+y)

3 0

3 years ago

An incomplete distribution is given below:Variable You are given that the median value is 70 and the total number of items is 20

expeople1 [14]

Answer:

The missing frequencies are x = 8 and y = 43.

Step-by-step explanation:

Median Value =70

Then the median Class =60-80

Let the missing frequencies be x and y.

Given: Total Frequncy = 200 , Median = 46

$\left|\begin{array}{c|ccccccc}Value&0-20&20-40&40-60&60-80&80-100&100-120&120-140\\Frequency&12&30&x&66&y&27&14\\$Cumu.Freq&12&42&42+x&108+x&108+x+y&135+x+y&149+x+y\end{array}\right|$

From the table

$\sum f_i =149+x+y$

Here, n = 200

n/2 = 100

Lower Class Boundary of the median class, l=60

Frequency of the median class(f) =66

Cumulative Frequency before the median class, f=42+x

Class Width, h=10

$Median = l + \dfrac{\dfrac{n}{2} - c.f }{f} \times h$

$70 = 60+ \dfrac{100- 42+x }{66}\times 10\\70 = 60+ \dfrac{58+x }{66}\times 10\\70-60=\dfrac{58+x }{66}\times 10\\10*66=10(58+x)\\58+x=66\\x=66-58\\x=8$

200=149+x+y

200=149+8+y

y=200-(149+8)

y=43

Hence, the missing frequencies are x = 8 and y = 43.

8 0

3 years ago